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3 years ago

PNEWTON What is the ist law of motion?

Physics

1 answer:

Degger [83]3 years ago

8 0

Answer:

Newton's First Law states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force. It may be seen as a statement about inertia, that objects will remain in their state of motion unless a force acts to change the motion.

Explanation:

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The earth has a vertical electric field at the surface, pointing down, that averages 119 N/C . This field is maintained by vario

velikii [3]

Answer:

$q=5.37*10^{5}C$

Explanation:

If we assume that the Earth is a spherical conductor, according to Gauss's Law, the electric field is given by:

$E=\frac{kq}{r^2}$

Here k is the Coulomb constant, the excess charge on the Earth's surface and r its radius. Solving for q:

$q=\frac{Er^2}{k}\\q=\frac{119\frac{N}{C}(6.371*10^6m)^2}{8.99\frac{N\cdot m^2}{C^2}}\\q=5.37*10^{5}C$

5 0

3 years ago

A quarter is flipped from a height of 1.45 m above the ground. How much time will it take to reach the ground if the person flip

Artemon [7]

It will take the quarter 0.151 seconds to reach the ground.

Given the following data:

Height = 1.45 meters

Initial velocity = 10.32 m/s

We know that acceleration due to gravity (a) for an object is equal to 9.8 meter per seconds square.

To find how much time it will take the quarter to reach the ground, we would use the second equation of motion.

Mathematically, the second equation of motion is given by the formula;

$S = ut + \frac{1}{2} at^2$

Where:

S is the height or distance covered.

u is the initial velocity.

a is the acceleration.

t is the time measured in seconds.

Substituting the values into the formula, we have;

$1.45 = 10.32(t) + \frac{1}{2} (9.8)t^2\\\\1.45 = 10.32t + 4.9t^2\\\\4.9t^2 + 10.32t - 1.45 = 0$

The standard form of a quadratic equation is:

$ax^2 + bx + c = 0$

a = 4.9, b = 10.32 and c = 1.45

We would solve the above quadratic equation by using the quadratic equation formula;

$x = \frac{-b\; \pm \;\sqrt{b^2 - 4ac}}{2a}$

Substituting the values, we have;

$t = \frac{-10.32\; \pm \;\sqrt{10.32^2\; - \;4(4.9)(1.45)}}{2(4.9)}\\\\t = \frac{-10.32\; \pm \;\sqrt{106.5024\; - \;28.42}}{9.8}\\\\t = \frac{-10.32\; \pm \;\sqrt{78.0824}}{9.8}\\\\t = \frac{-10.32\; \pm \;8.84}{9.8}\\\\t = \frac{-10.32\; + \;8.84}{9.8}\\\\t = \frac{1.48}{9.8}$

Time, t = 0.151 seconds.

Therefore, it will take the quarter 0.151 seconds to reach the ground.

Read more: brainly.com/question/8898885

3 0

3 years ago

- With the device starting from a still position (0 m/s), you drop it, allowing gravity to accelerate it towards the ground at 9

IrinaVladis [17]

Starting velocity (u)=0
acceleration (a) = 9.8
time (t) = 1.5
final velocity (v) =?

v=at+u
v=9.8(1.5)+0
v=14.7m/s2

3 0

3 years ago

Which expression is equivalent to g−m ÷ gn?

Vinvika [58]

Answer

(g²n - m)/(gm)

Explanation

g - m ÷ gn = g - m/gn

Make the equation have the same denominator

g - m ÷ gn = g - m/gn = (ggn)/gn - m/gn

= (g²n)/gn - m/gm

Since they have the same denominator, we can carry out the subtraction on the numerator and then put them under one denominator.

(g²n)/gn - m/gm = (g²n - m)/(gm)

5 0

3 years ago

A 1.005 m chain consists of small spherical beads, each with a mass of 1.00 g and a diameter of 5.00 mm, threaded on an elastic

LUCKY_DIMON [66]

Answer:

1) μ = 1.33 10⁻³ kg / m , F = - 14,256 , 2) v= 103.53 m/s, 3) f = 138.04 Hz , 4) 1, 25, 50, 76, 101 , 5) A = 0.00869 m , 6) # _position = (# _account-1) (1.5m / 100 accounts)

Explanation:

1) Linear density is the mass per unit length

μ = m / L

μ = 2 1 10⁻³ / 1,5

μ = 1.33 10⁻³ kg / m

this is the density when the chain is stretched, which is when the pulse occurs

we can find the tension with

F = - k (x₁-x₀)

where k is the spring constant

F = - 28.8 (1.5 -1.005)

F = - 14.256 N

the negative sign indicates that the force is restorative

2) the pulse speed is

v = √ T /μ

v = √ 14,256 / 1,33 10⁻³

v = 103.53 m / s

3) If standing waves are formed with fixed points at the ends and 4 antinodes, the wavelength is

2 λ = L

λ = L / 2

wave speed is related to frequency and wavelength

v = λ f

f = v / λ

f = v 2 / L

f = 103.53 2 / 1.5

f = 138.04 Hz

4) The marbles are numbered, the marbles that remain motionless are

the first (1) and the last (101)

Let's look for the distance to each node, for this we must observe that in each wavelength there is a node at the beginning, one in the center and one at the end, therefore the nodes are in

#_node = m λ / 2 = m L / 4

#_node position (m)

1 1.5 / 4 = 0.375

2 2 1.5 / 4 = 0.75

3 3 1.5 / 4 = 1,125

Since there are 101 marbles in the initial length, this number does not change with increasing length, so there is 101 marble in 1.5 m. Let's find with a direct proportion rule the number of marbles at these points with nodes

#_canica = 0.375 m (101 marble / 1.5 m) 0.375 67.33

# _canica = 25

#_canica = 0.75 67.33

#_canica = 50

# _canica = 1,125 67.33

#canica = 75.7 = 76

in short the number of the fixed marbles is

1, 25, 50, 76, 101 canic

5) The movement of the account is oscillatory at this point, which is why it is described by

y = A cos wt

$v_{y}$ = -A w sin wt

the speed is maximum for when the breast is worth ±1

v_{y} = Aw

A = v_{y} / w

angular velocity related to frequency

w = 2π f

A = v_{y} / 2πf

A = 7.54 / (2π 138.04)

A = 0.00869 m

6) for the position of each account we can use a direct proportion rule

in total there are 100 accounts distributed in the 1.50 m distance, the #_account is in the # _position. Note that it starts to be numbered 1, so this number must be subtracted from the index of the amount

# _position = (# _account-1) (1.5m / 100 accounts)

#_canic position(m)

1 0

2 0.015

3 0.045

4 0.06

7) the wave has a constant velocity, but every wave is oscillated perpendicular to this velocity, with an oscillatory movement described by the expression

y = Acos wt

the maximum speed is

$v_{y}$ = -Aw sin wt

speed is maximum when the sine is ±1

v_{y} = A w

to calculate the amplitude of the count we use that for a standing wave

y = 2Asin kx

y / A = 2 sin (2π /λ x)

the wavelength is

λ = 0.75 m

the position is

x (30) = 29 1.5 / 100 = 0.435 m

y (30) A = 2 sin (2pi 0.435 / 0.75)

y (30) / A = 0.96 m

8 0

4 years ago