Given that the diameter: d= 0.0625 inch.
So, radius of the wire : r = 
= 0.03125 inch
Now the formula to find the cross-sectional area of wire ( circle) is:
A = πr²
= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125
=3.14 * 0.000976563
= 0.003066406
= 0.00307 (Rounded to 5 decimal places).
Hence, cross-sectional area of a wire is 0.00307 square inches.
Hope this helps you!
1/5 this shows that each can be picked up at Least 1/5 or 2/10
X^2/(x- 9 = 81/(x - 9)
This is the equation for which you want the solution.
Multiplying both sides of the equation by (x - 9) we get
x^2(x - 9)/(x - 9) = 81(x - 9)/(x - 9)
So the (x - 9) goes out from both the denominator and the numerator and then the simplified equation becomes
x^2 = 81
x ^2 = (9)^2
x = 9
So the value of the unknown variable x comes out to be 9.
Step-by-step explanation:
A=2πr(r+h)
A=6.28×14mm(+29mm)
A=77.92(14mm+29mm)
A=77.92×43
A=3350.56 mm
Hope it helps
KC
