Answer:
Number of families that should be surveyed if one wants to be 90% sure of being able to estimate the true mean PSLT within 0.5 is at least 43.
Step-by-step explanation:
We are given that one wants to estimate the mean PSLT for the population of all families in New York City with gross incomes in the range $35.000 to $40.000.
If sigma equals 2.0, we have to find that how many families should be surveyed if one wants to be 90% sure of being able to estimate the true mean PSLT within 0.5.
Here, we will use the concept of Margin of error as the statement "true mean PSLT within 0.5" represents the margin of error we want.
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<u>SO, Margin of error formula is given by;</u>
Margin of error =
where,
= significance level = 10%
= standard deviation = 2.0
n = number of families
Now, in the z table the critical value of x at 5% (
) level of significance is 1.645.
SO, Margin of error =
0.5 =

n =
= 43.3 ≈ 43
Therefore, number of families that should be surveyed if one wants to be 90% sure of being able to estimate the true mean PSLT within 0.5 is at least 43.
Answer:
(4, -6)
Step-by-step explanation:
(x1+x2)/2 + (y1+y2)/2 = midpoint
(11+-3)/2 = 8/2 = 4. x = 4
(-5 + -7)/2 = -12/2. y = -6
4, -6 is the midpoint
give brainliest please! hope this helps :)
Answer:
false
Step-by-step explanation:
this beacuse when is times with the base that shows the product thats the factor
10v⁶y⁷ = <u>2</u> * 5 * <u>vvvvv</u>v * <u>yyy</u>yyyy
6w⁴v⁵y³ = <u>2</u> * 3 * wwww * <u>vvvvv</u> * <u>yyy</u>
GCF: 2v⁴y³
<em>The LCM is the GCF and everything leftover</em>
LCM: 2v⁴y³ * (5 * v * yyyy) * (3 * wwww)
= (2 * 5 * 3) * (v⁴ * v) * (w⁴) * (y³ * y⁴)
= 30 v⁵ w⁴ y⁷
Answer: LCM = 30v⁵w⁴y⁷