3. List three structures found in plant cells that are not in ani- mal cells. (7.1.b)

Calcium is a nontoxic metal that is used in supplements to maintain strong bones. Under high pressure conditions, over about 320

Lera25 [3.4K]

Explanation:

It is known that in a simple cubic unit cell the atoms are only present at the corner of the unit cell. This means that there are in total 8 atoms present in a simple cubic unit cell.

Therefore, in one simple cubic unit cell sharing of one atom is only $\frac{1}{8}$ .

Hence, the total number of atoms in a unit cell will be as follows.

$8 \times \frac{1}{8}$ = 1

Thus, we can conclude that there is 1 calcium atom present in each unit cell.

4 0

3 years ago

Which one is the answer?

nadya68 [22]

I would go with C because that seems like the best answer choice

3 0

3 years ago

Which statement is true about SO4 2− ?

Nonamiya [84]

It is a poly atomic anion because it has more than one atom and a negative charge

4 0

3 years ago

Read 2 more answers

How many chlorine ions are required to bond with one aluminum ion

Monica [59]

The answer is Three
!!!!!!

4 0

3 years ago

Which of the following isoelectronic series is correctly ranked from largest ionic radius to smallest ionic radius? 1. N 3−, O 2

love history [14]

Answer:

Option 1: N⁻³ > O⁻² > F⁻ > Na⁺ > Mg⁺²

Explanation:

Ionic radius is the radius of an atom´s ion in ionic crystal structure. In an ion that lose an electron, to form a cation, the radius of the ion gets smaller, because the repulsion between electrons decrease because fewer electrons are present. Conversely, adding on electron to a neutral atom, to form an anion, causes electron - electron repulsions to increase, so the size of the radius of the ion gets bigger.

Isoelectronic species are ions or elements that have the same number of electrons in their electronic shells but have different overall charges, because of their different atomic numbers.

In a isolelectronic series (same number of electrons), the increase of the positive charge (given by the number of protons in the nucleus), will cause a decrease in radius beacuse the greater electrostatic attraction between the electrons and the nucleus. Consequently, the ion with the greatest nuclear charge will have the smallest ionic radius and the ion with the smallest nulear charge will have the largest ionic radius.

We will use this principle to solve our problem.

In our case, the given ions are:

N⁻³ : Z = 7, e⁻ = 10
O⁻²: Z= 8, e⁻ =10
F⁻: Z = 9, e⁻ = 10
Na⁺: Z= 11, e⁻ = 10
Mg⁺²: Z=12, e⁻ =10

where Z= number of protons, and e⁻ = number of electrons.

Hence the decreasing order of ionic radius is:

N⁻³ > O⁻² > F⁻ > Na⁺ > Mg⁺²

Have a nice day!

4 0

3 years ago