Answer:
1. C4H8 + 6O2 -----> 4CO2 + 4H20
2. 3836.77 kcal
Explanation:
1. Balanced equation for the complete combustion of cyclobutane:
C4H8 + 6O2 -----> 4CO2 + 4H20
2. Heat of combustion of cyclobutane = 650.3 kcal/mol
Molecular weight of cyclobutane, C4H8 = 56.1 g/mol
Mole of C4H8 : mass of cyclobutane/Molecular weight of cyclobutane
Mole of C4H8 = 331/56.1 = 5.9 mol
Energy released during combustion = 5.9 mol × 650.3 kcal/mol = 3836.77kcal
Therefore the energythat is released during the complete combustion of 331 grams of cyclobutane is 3836.77kcal
Answer:
1. The balanced equation is given below:
C4H6O3 + H2O → 2C2H4O2
The coefficients are: 1, 1, 2
Explanation:
C4H6O3 + H2O → C2H4O2
The above equation can be balanced as follow:
There are 4 atoms of C on the left side and 2 atoms on the right side. It can be balance by putting 2 in front of C2H4 O2 as shown below:
C4H6O3 + H2O → 2C2H4O2
Now, the equation is balanced as the number of atoms of the different elements present on both sides of the equation are equal.
The coefficients are: 1, 1, 2
When we are performing IR spectroscopy for Cyclohexane and cyclohexene, we can distinguish them as cyclohexene has C-H carbon-hydrogen stretching so, it shows the absorption at 3000-2850 cm⁻¹ range, where the cyclohexane do not have this and it shows the -C=C- stretch at 1640-1680 cm⁻¹ range in the spectrum. So that is how we can distinguish both.
14109 is the nearest gram