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-BARSIC- [3]
3 years ago
14

A student measures a volume as 25 mL, whereas the correct volume is 23 mL. What is the percent error? * O 8.7% O 0.92% O 0.087%

08.0%​
Chemistry
2 answers:
quester [9]3 years ago
5 0

Answer:

no u

Explanation:

vlabodo [156]3 years ago
5 0
Ik hell h rn hold up let me do the math
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How many moles of glucose (C6H12O6) are in 1.5 liters of a 4.5 M C6H12O6 solution
Natalija [7]
M=n/V , 4.5=n/1.5 , (45/10). (15/10)=n , (9/2).(3/2)=n=27/4 , n=6,75
3 0
4 years ago
PLZZ HELP!!!
pashok25 [27]
The sun evaporates the water from a stream or some type of water source and it then gets collected  into the clouds and then condensation and the last step is when the water is too heavy so the clouds release it and that is called precipitation. hope this helps.
5 0
4 years ago
Each glucose molecule consists only of carbon, hydrogen, and oxygen atoms. If each molecule contains 53.3% oxygen and 6.7% hydro
MAVERICK [17]
53.3% + 6.7% = 60%, 100% - 60% = 40%. 40% of glucose is made of carbon. Since there are only three types of atoms in glucose, and the amount of hydrogen and oxygen is already given, this means that whatever percentage is left (40%) has to be carbon.
8 0
4 years ago
Urgent plzz help meeee thx
MakcuM [25]

Answer:

8

Explanation:

From the question given above, the following data were obtained:

t–butyl ion = (CH₃)₃C⁺

Number of valence electron =?

The valence electron(s) talks about the combining power of an element or compound as the case may be.

Considering the t–butyl ion, (CH₃)₃C⁺ we can see that it has a charge of +1 indicating that it has given out 1 electron to attain the stable octet configuration which has a valence electrons of 8. Thus, the valence electron of t–butyl ion, (CH₃)₃C⁺ is 8

5 0
3 years ago
How many grams of Co are needed to react with an excess of fe203 to produce 156.2 g FE? show your work.
Gekata [30.6K]

The reaction is given as

Fe2O3 (s)+ 3CO(g)--->3CO2(g)+ 2Fe(s)

No.of moles=mass in gram/molar mass

As for Fe mole =156.2g/55.847=2.7969~2.797

The ratio b/w CO and Fe is 3:2

Moles of CO needed= 2.797x3/2=4.1955

Mass of CO needed= 4.195mol x 28.01g/mol= 117.515g

8 0
4 years ago
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