Answer:
√(81/9)
(It is equal to 3)
Step-by-step explanation:
Answer:
Juan
Step-by-step explanation:
The number of pages that Ana, Hillary, Roger, and Juan can read in a day is shown below:
For Ana
Ana read 15% of her 46-page book.
= 15% × 46 pages
= 6.9 pages
For Hillary
Hillary read 11% of her 72-page book.
= 11% × 72 pages
= 7.92 pages
For Roger
Roger read 12% of his 68-page book.
= 12% × 68 pages
= 8.16 pages
For Juan
Juan read 14% of his 69-page book.
= 14% × 69 pages
= 9.66 pages
The person who can read greatest number of pages in a day also means the person who read the highest number of pages in a day.
From the calculation above, that person in JUAN because she can read 9.66 pages of her book in one day.
Depending on what you're supposed to do, the three could either mean to distribute it into the equation, giving you
either
(3*2015) or (3*20)*(3*15) or (3*20) +/- (3*15)
Or an example of factoring where they took 3 out of 60 and 45.
There are no instruction on what to do in this question.
13 x 12 = 156 in<span>2 Hope I could help :)</span>
Answer:
The probability that no more than more than 11 of them need correction for their eyesight is 0.00512
No, 11 is not a significantly low low number of adults requiring eyesight correction .
Step-by-step explanation:
A survey showed that 77% of adults need correction for their eyesight.
If 22 adults are randomly selected, find the probability that no more than more than 11 of them need correction for their eyesight.
n =22
p = 0.77
q = 1-p = 1- 0.77=0.23
We are supposed to find ![P(x\leq 11)](https://tex.z-dn.net/?f=P%28x%5Cleq%2011%29)
![P(x\leq 11)=P(x=1)+P(x=2)+P(x=3)+.....+P(x=11)](https://tex.z-dn.net/?f=P%28x%5Cleq%2011%29%3DP%28x%3D1%29%2BP%28x%3D2%29%2BP%28x%3D3%29%2B.....%2BP%28x%3D11%29)
Formula : ![P(x=r)=^nC_r p^r q^{n-r}](https://tex.z-dn.net/?f=P%28x%3Dr%29%3D%5EnC_r%20p%5Er%20q%5E%7Bn-r%7D)
![P(x\leq 11)=^{22}C_1 (0.77)^1 (0.23)^{22-1}+^{22}C_2 (0.77)^2 (0.23)^{22-2}+^{22}C_3 (0.77)^1 (0.23)^{22-3}+.....+^{22}C_{11} (0.77)^1 (0.23)^{22-11}](https://tex.z-dn.net/?f=P%28x%5Cleq%2011%29%3D%5E%7B22%7DC_1%20%280.77%29%5E1%20%280.23%29%5E%7B22-1%7D%2B%5E%7B22%7DC_2%20%280.77%29%5E2%20%280.23%29%5E%7B22-2%7D%2B%5E%7B22%7DC_3%20%280.77%29%5E1%20%280.23%29%5E%7B22-3%7D%2B.....%2B%5E%7B22%7DC_%7B11%7D%20%280.77%29%5E1%20%280.23%29%5E%7B22-11%7D)
Using calculator
![P(x\leq 11)=0.00512](https://tex.z-dn.net/?f=P%28x%5Cleq%2011%29%3D0.00512)
So, The probability that no more than more than 11 of them need correction for their eyesight is 0.00512
No, 11 is not a significantly low low number of adults requiring eyesight correction .