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marta [7]
3 years ago
9

F(-5) = -4, and f(5)= 2 linear equation satisfying the conditions , if possible

Mathematics
1 answer:
san4es73 [151]3 years ago
4 0

Given:

f(-5) = -4, and f(5)= 2.

To find:

The linear equation satisfying the conditions.

Solution:

We have,

f(-5) = -4, and f(5)= 2

It means the function passes through the points (-5,-4) and (5,2). So, the linear equation of the function f is

y-y_1=\dfrac{y_2-y_1}{x_2-x_2}(x-x_1)

y-(-4)=\dfrac{2-(-4)}{5-(-5)}(x-(-5))

y+4=\dfrac{2+4}{5+5}(x+5)

y+4=\dfrac{6}{10}(x+5)

On further simplification, we get

y+4=\dfrac{3}{5}(x+5)

y+4=\dfrac{3}{5}x+3

y=\dfrac{3}{5}x+3-4

y=\dfrac{3}{5}x-1

Putting y=f(x), we get

f(x)=\dfrac{3}{5}x-1

Therefore, the required function is f(x)=\dfrac{3}{5}x-1.

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Answer:

\sqrt{8}----- 2units,2units

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Step-by-step explanation:

Use pythagorean's theorem to solve each pair individually.

The instructions say that you have the two sides (a and b) and you have to match it with their hypothenuse.

Formula: c^2=a^2+b^2

1. a=\sqrt{5}, b=\sqrt{2}

Plug this into the formula.

c=\sqrt{(\sqrt{5} )^2+(\sqrt{2})^2 }

The square here eliminates the roots.

c=\sqrt{5+2}\\ c=\sqrt{7}

2. a=\sqrt{3}, b=4

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3. a=2, b=\sqrt{5}

c=\sqrt{(2)^2+(\sqrt{5})^2 }\\ c=\sqrt{4+5}\\ c=\sqrt{9}\\ c=3

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5. a=1, b=2

c=\sqrt{(1)^2+(2)^2}\\ c=\sqrt{1+4}\\ c=\sqrt{5}

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3 years ago
What is the inverse of f(x)=3x-1
tatiyna

Answer:

$ \frac{(y + 1)}{3} $

Step-by-step explanation:

Call $ f(x) = y = 3x - 1 $

Now, $ y + 1 = 3x $

$ \implies \frac{y + 1}{3} = x $

This is the inverse of the given function.

You can cross - verify it by substituting a point, say, $ (1,3) $

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4 years ago
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Step-by-step explanation:

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This is the equation:

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4 0
3 years ago
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Answer: There are 35 spellers participated in the spelling bee.

Step-by-step explanation:

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