Your "<span>h (x)=x 2 squared +6x-3" is ambiguous. If you meant "x squared," then you need only write x^2 OR "x squared," but NOT "x 2 squared."
I will assume that by "</span><span>h (x)=x 2 squared +6x-3" you actually meant:
</span><span>h(x)=x^2 +6x-3. To find h(3), subst. 3 for x: h(3) = (3)^2 + 6(3) - 3, or
h(3) = 9 + 18 - 3, or h(3) = 24.</span>
Answer:
boys = 705
girls = 783
Step-by-step explanation:
We are to find the number of boys and girls in the school
the answer can be determined using simultaneous equation
x = boys
y = girls
y - x = 78 equation 1
y + x = 1488 equation 2
subtract equation 1 from 2
2x = 1410
x = 1410/2 = 705
Substitute for x in equation 1
y - 705 = 78
y = 705 + 78 = 783
x + y = 4,000
0.1x + 0.04y = 352
Product A represents x and product B represents y. The first equation is the total number of items the store owner buys. The second equation is cost per item for both products. The above system of equations can be used to determine how much product A and product B the store owner bought.
