Logx (8x-3) - logx 4 = 2
logx [(8x-3)/4] = 2
x^2=(8x-3)/4
4x^2=4(8x-3)/4
4x^2=8x-3
4x^2-8x+3=8x-3-8x+3
4x^2-8x+3=0
4(4x^2-8x+3=0)
(4^2)(x^2)-8(4x)+12=0
(4x)^2-8(4x)+12=0
(4x-2)(4x-6)=0
2(4x/2-2/2)2(4x/2-6/2)=0
4(2x-1)(2x-3)=0
4(2x-1)(2x-3)/4=0/4
(2x-1)(2x-3)=0
Two options:
1) 2x-1=0
2x-1+1=0+1
2x=1
2x/2=1/2
x=1/2
2) 2x-3=0
2x-3+3=0+3
2x=3
2x/2=3/2
x=3/2
Answer: Two solutions: x=1/2 and x=3/2
Answer: 0.01
Step-by-step explanation:
Let the events are :
C = paving stones found to be cracked.
D = paving stones found to be discolored.
Given : Total stones : T = 600 (i)
C = 15
D= 27
C'∩D'= 564 (ii)
Since C'∩D' = (C∪D)' = T- C∪D (iii)
From (i) , (ii)and (ii) , we have
564 = 600- C∪D
⇒ C∪D=600- 564= 36
Formula : C∩D= C+D- C∪D
Put values , we get
C∩D= 15+27-36=6
Now ,

The probability that it is both cracked and distorted is 0.01.
Answer:
B) |x-1|≤3
Step-by-step explanation:
B) |x-1|≤3
If you substitute in any number (-2 through 4), this inequality is correct.