<span>Given: ΔABC
When written in the correct order, the two-column proof below describes
the statements and justifications for proving the three medians of a
triangle all intersect in one point are as follows:
Statements Justifications
Point F
is a midpoint of Line segment AB </span><span>by Construction
Point E is a midpoint of Line segment
AC
Draw Line segment BE
Draw Line segment FC
Point G is
the point of intersection between
Line segment BE and Line segment FC Intersecting Lines Postulate
Draw Line segment AG by Construction
Point D
is the point of intersection between
Line segment AG and Line segment
BC Intersecting Lines Postulate
Point H lies on Line segment AG such
that
Line segment AG ≅ Line segment GH by Construction
</span><span>Line segment FG is parallel to line segment
BH and Line
segment GE is parallel to line
segment HC Midsegment Theorem
</span><span><span>Line
segment GC is parallel to line segment
BH and Line segment BG is
parallel to
line segment HC Substitution</span>
</span>BGCH is a <span><span><span><span>Properties of a Parallelogram </span>parallelogram (opposite sides are parallel)</span>
</span>Line segment BD
≅ Line segment </span><span><span>Properties of a Parallelogram </span>DC (diagonals bisect each
other)
Line segment
AD is a median Definition of a Median</span>
Thus the most logical order of statements and justifications is: II, III, IV, I
Answer:
hi
Step-by-step explanation:

Please find attached photograph for your answer.
Hope it helps.
Do comment if you have any query.
Answer:
Option B: 
Step-by-step explanation:
When the focus (h, k) of a parabola and the equation of the directrix y = c are given, the equation of the parabola is given by:

Here, we are given the focus: (h, k) = (0, -2)
Directrix: y = c = -3.
We substitute in the formula to get the equation of the parabola.




Dividing by 2, throughout we get:
which is the required answer.
2/5 because 10/10 minus 6/10 equals 4/10 which reduces to 2/5