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2 years ago

11

At the skating rink, 6 out 10 skaters were able to skate under the limbo bar. Which names the fraction of skaters who were not a

ble to skate under the limbo bar?

1 answer:

Tasya [4]2 years ago

7 0

2/5 because 10/10 minus 6/10 equals 4/10 which reduces to 2/5

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PLEASE HELP 99 POINTS PLUS BRAINIEST ANSWER.

Mrac [35]

1. Percent error is $| \frac{guess-actual}{actual}|$
The guess is 15.5mi, and the actual distance is 14.5 mi.
Percent error is $| \frac{15.5-14.5}{14.5}|=0.69=6.9%$

2. The cost will be $31.95*(1+0.075) = $34.35
The 1 represents 100% of the original amount of $31.95, and now we add 7.5% (0.075) to the 100%. In other words we multiply $31.95 by 107.5%.

3. His commission will be $165 out of $4125, or $165/$4215 = 0.039 = 3.9%

4. The principal (amount of money you start with) is $12000, and the interest rate is 15% of that.
15% of $1800 = 0.15*$12000 = $1800

4 0

2 years ago

Read 2 more answers

Pls help!! what is x

faust18 [17]

Answer:

x is a variable to fill in something that is unknown. its like a question mark

Step-by-step explanation:

4 0

2 years ago

Can someone please answer. There is one problem. There's a picture. Thank you!

lidiya [134]

The second choice is the correct one.

3 0

3 years ago

Read 2 more answers

For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.

Anni [7]

Answer:

The reduced row-echelon form of the linear system is $\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

Interchange two rows
Multiply one row by a nonzero number
Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

$\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]$

You need to follow these steps:

Divide row 1 by 2 $\left(R_1=\frac{R_1}{2}\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]$

Subtract row 1 from row 2 $\left(R_2=R_2-R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]$

Subtract row 1 multiplied by 5 from row 3 $\left(R_3=R_3-\left(5\right)R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 1 $\left(R_1=R_1-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 3 $\left(R_3=R_3-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]$

Multiply row 2 by 2 $\left(R_2=\left(2\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]$

Divide row 3 by −19 $\left(R_3=\frac{R_3}{-19}\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]$

Subtract row 3 multiplied by 16 from row 1 $\left(R_1=R_1-\left(16\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right]$

Add row 3 multiplied by 6 to row 2 $\left(R_2=R_2+\left(6\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

8 0

3 years ago

Write an equation of a line perpendicular to the line y = -1/5x + 3 and goes through the point (-5, 6), then use Point- Slope fo

lorasvet [3.4K]

The answer is that the equation y=5x+31 is perpendicular to the equation y=-1/5x+3 and that equation passes through (-5,6) also y=5x+31 is in y=mx+b form already
y=mx+b

4 0

3 years ago