Question

A skateboarder starts from rest and maintains a constant forward acceleration of 0.50 meter per second squared for 8.4 s. what is the rider’s displacement during this time?

Answer 1

Answer-

The rider’s displacement during this time is 17.01 m

Solution-

As we know,

$s= ut + \frac{1}{2}at^{2}$

Where s = displacement,

           u= initial velocity = 0, as the rider starts from rest

           a= acceleration = 0.5 m/s²

           t= time taken = 8.4 s

Putting the values,

$s = (0)(8.4) + \frac{1}{2} (0.5)(8.4)^{2} = 17.64 \ m$

Answer 2

Answer:

Step-by-step explanation:

a=0.50

t=8.4s

initial velocity=0

0+1/2*0.50*8.4^2=17.64m

17.6