All categories

3 years ago

What is the area to my question

Mathematics

1 answer:

Alex787 [66]3 years ago

6 0

Answer:

Step-by-step explanation:

Find the area of the triangle and subtract that from the area of the rectangle to get your answer.

32-[(4*2)/2]

32-4

You might be interested in

If two circles have the same circumference what do you know about their area

Usimov [2.4K]

If the circumference is half of the perimeter than the area for both circles would be half of them find one circles area and half it

8 0

3 years ago

Write an expression for the calculation 84 divided into sevenths added to 9 divided into thirds

kogti [31]

(84/7)+ 9/3=
12+9/3
12+3
15

7 0

4 years ago

Ice cream vs temperature

ollegr [7]

answer is probably ice cream

7 0

3 years ago

Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega

AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

To find the simplified form of the given expression :

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

$=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2$ ( using the property $(ab)^m=a^m.b^m$ )

$=(2^6)(3^{-12})\times (2^{-6})(3^4)$ ( using the property $(a^m)^n=a^{mn}$

$=(2^6)(2^{-6})(3^{-12})(3^4)$ ( combining the like powers )

$=2^{6-6}3^{-12+4}$ ( using the property $a^m.a^n=a^{m+n}$ )

$=2^03^{-8}$

$=\frac{1}{3^8}$ ( using the property $a^{-m}=\frac{1}{a^m}$ )

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

6 0

3 years ago

Read 2 more answers

Which of the following correctly shows the quadratic formula for the given equation? 3x2 - 6x + 8 = 0

frez [133]

The quadratic formula is expressed as:

x = (-b +/- √(b^2 - 4ac) ) / 2a

where a, b and c are the coefficients of the quadratic equation with the form ax^2 + bx + c=0

Therefore, the quadratic equation would be:

a = 3
b = -6
c = 8

x = (-(-6) +/- √((-6)^2 - 4(3)(8) ) / 2(3)

Hope this helps.

7 0

3 years ago