What number would represent 15 degrees below zero? *

What is the midpoint of the line segment with endpoints (-10, 9) (6, -7)

MrMuchimi

The midpoint is (-2, 1)

4 0

2 years ago

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Write the following sum using summation notation -2/5+3/6-4/7........11/14

horrorfan [7]

Answer:

$\sum_{n=1}^{10}(-1)^n\left ( \frac{n+1}{n+4} \right )$

Step-by-step explanation:

Given: $\frac{-2}{5}+\frac{3}{6}-\frac{4}{7}+...+\frac{11}{14}$

To write: the given expression using summation notation

Solution:

Summation notation helps to write a long sum as a single expression.

In the summation notation, the variable $\sum$ is called the index of summation.

Let $x_1,x_2,x_3,...,x_n$ denote a set of n numbers.

Then in summation notation,

$x_1+x_2+x_3+...+x_n=\sum_{i=1}^{n}x_i$

$\frac{-2}{5}=(-1)^1\left ( \frac{1+1}{1+4} \right )\\\frac{3}{6}=(-1)^2\left ( \frac{2+1}{2+4} \right )\\\frac{-4}{7}=(-1)^3\left ( \frac{3+1}{3+4} \right )\\.\\.\\.\\\frac{11}{14}=(-1)^10\left ( \frac{10+1}{10+4} \right )\\\therefore \frac{-2}{5}+\frac{3}{6}-\frac{4}{7}+...+\frac{11}{14}=\sum_{n=1}^{10}(-1)^n\left ( \frac{n+1}{n+4} \right )$

3 0

2 years ago

Find the missing side

mr_godi [17]

Answer:

Step-by-step explanation:

c^2 = a^2 - b^2

13^2 - 5^2 = -12

6 0

3 years ago

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On a circular playground, the distance from its center to the edge of the playground is 36 feet. What is the approximate circumf

hammer [34]

B
36 is the radius so
The formula for circumference is radius times two and take that answer times pi
So 36×2 is 72 and 72 times pi is 226.194671058

4 0

2 years ago

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What is the partial product for 652 x 4= 2,608

Law Incorporation [45]

To find out the answer of the two multiplied products with the help of partial products we separate into unit based numbers so as to, for easier calculation and simplification with units of zeroes. So, in this case we are given the product of 4 times of 652.

Here we need to expand this product of higher number to zeroes and take aside the added numbers to come back to the original multiple of a product. That is:

$\huge{652}$

$\begin{bmatrix}652 \\ + \\ 0 \end{bmatrix}$

We just separated and expanded the product to be multiplied by removing other units following it. Same goes for other units at Hundredth, tenth and unitary position.

Therefore,

$\begin{bmatrix}600 \\ + \\ 52 \end{bmatrix}$

For tenth term.

$\begin{bmatrix}50 \\ + \\ 2 \end{bmatrix}$

The terms after splitting and expanding the product before multiplication is:

$\begin{bmatrix}600 \\ 50 \\ 2 \end{bmatrix}$

Multiply the product elements in individual manner and add the elements forged by individual multiplication to get the required solution.

$\therefore \quad \begin{bmatrix}600 \times 4 \\ 50 \times 4 \\ 2 \times 4 \end{bmatrix}$

$\begin{bmatrix}600 \times 4 \\ + \\ 200 \\ + \\ 2 \times 8 \end{bmatrix}$

$\begin{bmatrix}2400 \\ + \\ 200 \\ + \\ 2 \times 8 \end{bmatrix}$

$\begin{bmatrix}2600 \\ + \\ 8 \end{bmatrix}$

$\boxed{\mathbf{Final \: \: Answer \: = \: 2,608}}$

Hope it helps.

8 0

3 years ago