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WINSTONCH [101]
3 years ago
13

There are 150 children in middle school.30% of the students are 6th graders. How many 6th graders are at CPCS?

Mathematics
2 answers:
IceJOKER [234]3 years ago
6 0

Answer:

45 children

Step-by-step explanation:

30% of 150=45

algol [13]3 years ago
4 0

Answer:

45 6th graders

Step-by-step explanation:

30% of 150 is 45

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A polygon is regular when all angles are equal and all sides are equal <br><br> True or False
Vesna [10]

Answer:

True

Step-by-step explanation:

True, because a polygon have all angles that are equal and all lengths are the same length.

4 0
3 years ago
This question worth 38 points to whoever answers it :)
Paraphin [41]
Volumeprism=volumecube times number of cubes
vprism/vcube=number of cubes

vprism=12*5*4.25=255
vcube=side^3=(1/4)^3=1/64

vprism/vcube=255/(1/64)=255*64=16320 cubes

4 0
3 years ago
Read 2 more answers
About 543 out of every 1,000 people in United States owned a cell phone in 2003.In japan,the are was 68 for every 100 people.How
Softa [21]

Answer:

The greater percent of cell phone ownership in Japan than the U.S was <u>13.7%</u>.

Step-by-step explanation:

Given:

About 543 out of every 1,000 people in United States owned a cell phone in 2003.

In japan,the are was 68 for every 100 people.

Now, to find the greater percent of cell phone ownership in Japan than the U.S.

So, to get the percent of people owned cell phone in United States:

\frac{543}{1000}\times 100

=0.543\times 100

=54.3\%.

Now, to get the percent of people owned cell phone in Japan:

\frac{68}{100} \times 100\\\\=0.68\times 100\\\\=68\%.

So, to get the percent greater of cell phone ownership in Japan than the U.S we subtract the percent of people owned cell phone in United States from the percent of people owned cell phone in Japan:

68\%-54.3\%\\\\=13.7\%.

Therefore, the greater percent of cell phone ownership in Japan than the U.S was 13.7%.

5 0
3 years ago
Please help... I really need this.
valentinak56 [21]

Answer:

\frac{4x^3-3x^2+5x+6}{x+6}=4x^2-27x+167-\frac{996}{x+6}

Step-by-step explanation:

The division problem given to us is (4x^3-3x^2+5x+6)\div (x+6).

To perform the synthetic division, we write out the coefficient of the polynomial. We set the linear factor to zero and solve for x, this becomes our divisor. That is x+6=0\implies x=-6.

We carry out the synthetic division as shown in the attachment.

The result of the synthetic division is 4   -27   167   -996

The first three terms are the coefficients of the quotient and the last term is the remainder.

Therefore the quotient is q(x)=4x^2-27x+167 and the remainder is r(x)=-996.

The dividend, the quotient and the divisor are written as

\frac{4x^3-3x^2+5x+6}{x+6}=4x^2-27x+167-\frac{996}{x+6}

The correct answer is A

3 0
3 years ago
Will Mark The Brainiest that is extra points aka FULL POINTS
valentina_108 [34]
Hello!

We can solve this by using substitution

we can plug y = x - 1 into the other equation

So 2x - 3( x - 1) = -1

We can distribute the -3 to (x - 1)

2x - 3x + 3 = -1

Combine like terms

-x + 3 = -1

Subtract 3 from both sides

-x = -4

Since x is negative we can multiply both sides by -1

x = 4

We can plug x into the first equation

y = (4) - 1

y = 3

The answers are x = 4 and y = 3

Hope this helps!
6 0
3 years ago
Read 2 more answers
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