Should I add anything? Is this good? Should I change something?

Mathematics

2 answers:

Leto [7]3 years ago

8 0

Answer:

its perfect! very cute

Pavel [41]3 years ago

7 0

It looks good. Don’t change anything. Great job.

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ITS URGENT PLEASE HELP Which equation represents the line that is parallel to y=3/7x+11 and passes through (-21,42)?

Pepsi [2]

Answer:

y = 3/7x + 51

Step-by-step explanation:

y = 3/7x + 11 is parallel to the line so it means that both of their gradient are same so:

y = mx + c

m= gradient point = (-21 , 42)

= 3/7

now we sub the m and the point into the formula which is y= mx+c because we should find the c first then we can find the equation of the line:

42 = 3/7 (-21) + c

42 = -9 + c

42 + 9 = c

51 = c

c = 51

now you hv to rewrite again the equation become y= 3/7x + 51

So now your final answer is : y = 3/7x +51

3 0

3 years ago

What is the oblique asymptote of the function f(x) x^2+x-2/x+1

Mamont248 [21]

$f(x)=\displaystyle\frac{x^2+x-2}{x+1}=\frac{x(x+1)-2}{x+1}=x-\frac{2}{x+1}
$

$\displaystyle\lim_{x\to\infty}\left\{f(x)-x \right\}=\lim_{x\to\infty}\frac{2}{x+1}=\lim_{x\to\infty}\frac{\displaystyle\frac{2}{x}}{1+\displaystyle\frac{1}{x}}
=0$

Consequently, the limit of $f(x)$ as x approaches infinity is $x$ .

In other words, $f(x)$ approaches the line y=x,

so oblique asymptote is y=x.

I'm Japanese, if you find some mistakes in my English, please let me know.