Answer:
6.9%.
Step-by-step explanation:
Given that a university class has 26 students: 12 are art majors, 9 are history majors, 5 and are nursing majors, and the professor is planning to select two of the students for a demonstration, where the first student will be selected at random, and then the second student will be selected at random from the remaining students, to determine what is the probability that the first student selected is a history major and the second student is a nursing major the following calculations must be performed:
26 = 100
9 = X
9 x 100/26 = X
900/26 = X
34.61 = X
25 = 100
5 = X
500/25 = X
20 = X
0.2 x 0.3461 = X
0.069 = X
Thus, the probability that the first student selected is a history major and the second student is a nursing major is 6.9%.
I believe the correct answer is a hope this helps
Answer:
k = -1/240
Step-by-step explanation:
to evaluate the value of k in the expression 1/3k+80=1/2k+120
we have
1/3k+80=1/2k+120
collect the like terms for easy evaluation
1/3k - 1/2k = 120 -80
1/3k - 1/2k = 40
find the lcm
2 - 3/6k = 40
-1/ 6k = 40
cross multiply
6k x 40 = -1
240k = -1
divide both sides by 240
240k/240 = -1/ 240
k = -1/240
therefore the value of k in the expression 1/3k+80=1/2k+120 is equals to -1/240
Answer:
6) The median is 80
7) The 1st quartile is 60
8) The 3rd quartile is 100
9) The minimum value is 40
10) The maximum value is 110
Step-by-step explanation:
Line up where the points are
Write and solve an equation of ratios:
5 *10^9 years 100 m
------------------- = --------------
5 * 10^3 yrs x
Reducing the first fraction,
100 m
10^6 = ----------
x
100 m
Solving for x, x = ------------- = 10^(-4) m, or [10^(-1)] * [10^(-3))]
10^6
this comes out to one tenth of 1 millimeter.
