Answer:
How far did the ship travel between the two observations of the lighthouse = 9.29
Step-by-step explanation:
the first step to answer this question is drawing the illustration as the attachment.
P is the ship, R is the light house and Q is the bearing.
PR is the distance between the ship and the light house, PR = 10.5
∠P = 42.8°, ∠Q = 59.7°
Thus, ∠R = 180° - ∠P - ∠Q
= 180° - 42.8°- 59.7°
= 77.5°
PQ is the the distance of the ship moving. We can use the sinus equation
= 
= 
PQ = (
)(sin 59.7°)
= 9.29
1) y = x
2) y = -(1/5)x + 4
3) y = -6x + 2
4) y = x + 2
5) y = (1/2)x + 2
6) y = -x + 4
7) y = -x + 1
8) y = (3/2)x + 2
9) y = -(3/2)x - 2
10) y = 2x - 1
Answer:
Step-by-step explanation:
160lb.
The mean of the weights of a group of 100 men and women is 160lb. If the number of men in the group is 60 and the mean weight of the men is 180lb, what is the mean weight of the women? For a set of data, the lower quartile is 19, the median is 31, and the upper quartile is 48.
Answer: 105 miles
Step-by-step explanation:
You can write an equation for this problem and solve it.
32 miles=1/3x-3, where x is equal to the total length of the highway.
35=1/3x, and then you multiply by 3, to get x=105
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❖ The length of the field is 91 m.
Divide to find the missing length:
4641 ÷ 51 = 91
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