The frequency of the second class is 6.
Since the class width is 6 and the lower limit of the first class is 50, this means the first class goes from 50-55. This would put the second class at 56-61. There are 6 data points in this set that would go in the second class.
Answer:
C
Step-by-step explanation:
It is C because members in the set C can be found in the universal set (U)
We know that angle MKJ is comprised of angle MKL and angle LKJ. That means if we add MKL and LKJ, we should get 80 degrees, which is the measure of angle MKJ.
So, we know that our x is 15. That is not enough to tell whether KL is an angle bisector, because we have to evaluate both MKL and LKJ with x=15, so:
So we see that these two angles are actually bisectors, and the third question best describes this phenomenon.
Answer:
12 units
Step-by-step explanation:
there are 3 sqaures counted from (0,0) to (3,0)
so do 3 + 3 + 3+ 3 and get 12 units
if brainiest is earned its greatly Appreciated
Answer: It is Geometric.
Step-by-step explanation: Because it does not have a fixed pattern that adds or subtract which arithmetic does.
