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2 years ago

12

Which of the following ordered pairs could be placed in the table and still have the relation qualify as a linear function? (4 p

oints)
Group of answer choices

(1, 7)

(−1, 13)

(2, 13)

(2, 7)

2 answers:

Sophie [7]2 years ago

8 0

Your answer would be (2,13)

Lerok [7]2 years ago

7 0

Answer:

(2, 7)

Step-by-step explanation:

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The football team has a total of 25 jerseys. There are 15 medium sized jerseys. What percent of the jerseys are medium sized jer

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the answer for your question is 60%

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3 years ago

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NO LINKS!!! Kim invested $5000 in Mutual fund at 6% compounded quarterly. Write an equation to represent this situation. When wi

Ira Lisetskai [31]

Answer:

Equation is A = 5000(1.015)^(4t)

Her investment will be worth $10,000 in about <u>11.63888 years</u>

Rounding up to the nearest whole number gets to <u>12 years</u>

==========================================================

Explanation:

Part 1) Finding the equation

The compound interest formula is

A = P(1+r/n)^(n*t)

Here are the variables

A = final amount
P = starting amount, or deposit, or principal
r = interest rate in decimal form
n = number of times money is compounded per year
t = number of years

In this case,

P = 5000
r = 0.06 from the 6% annual interest
n = 4 times a year is the compounding frequency
t = unknown amount of time

Therefore, the equation is

A = P(1+r/n)^(n*t)

A = 5000(1+0.06/4)^(4t)

A = 5000(1.015)^(4t)

The decimal value is exact.

--------------------------

Part 2) Let's plug in A = 10,000 and solve for t.

You'll need to use logarithms to isolate the exponent.

A = 5000(1.015)^(4t)

10,000 = 5000(1.015)^(4t)

10,000/5000 = (1.015)^(4t)

2 = (1.015)^(4t)

Log[ 2 ] = Log[ (1.015)^(4t) ]

Log(2) = 4t*Log( 1.015 )

4t = Log(2)/Log(1.015)

4t = 46.5555256308062

t = 46.5555256308062/4

t = 11.6388814077015

t = 11.63888

It takes about 11.63888 years for the investment to reach $10,000.

Therefore, at the 12 year mark is when the investment is more than $10,000.

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1 year ago

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How can I find the answer?

KonstantinChe [14]

Answer:put two triangles in the first three squares in the second and four triangles and two squares in the thrif

Step-by-step explanation:

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3 years ago

The formula for computing compound interest for a principal P that is invested at an annual rate r and compounded annually is gi

maria [59]

9514 1404 393

Answer:

r ≈ 6%

Step-by-step explanation:

Solving for r when n=2, we have ...

$A=P(1+r)^2\\\\\dfrac{A}{P}=(1+r)^2\\\\\sqrt{\dfrac{A}{P}}=1+r\\\\\boxed{r=\sqrt{\dfrac{A}{P}}-1}$

For the given values of A and P, the value of r is ...

$r=\sqrt{\dfrac{5600}{5000}}-1=\sqrt{1.12}-1\approx 1.0583-1\\\\\boxed{r\approx 6\%}$

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3 years ago

Write a quadratic equation given the roots -1/3 and 5, show your work

Travka [436]

$\boxed{(x - a)(x - b) = 0}$

The equation above is the intercept form. Both a-term and b-term are the roots of equation.

$x = - \frac{1}{3} \\ x = 5$

These are the roots of equation. Therefore we substitute a = - 1/3 and b = 5 in the equation.

$(x + \frac{1}{3} )(x - 5) = 0$

Here we can convert the expression x+1/3 to this.

$x + \frac{1}{3} = 0 \\ 3x + 1 = 0$

Rewrite the equation.

$(3x + 1)(x - 5) = 0$

Simplify by multiplying both expressions.

$3 {x}^{2} - 15x + x - 5 = 0 \\ 3 {x}^{2} - 14x - 5 = 0$

<u>Answer</u><u> </u><u>Check</u>

Substitute the given roots in the equation.

$3 {(5)}^{2} - 14(5) - 5 = 0 \\ 75 - 70 - 5 = 0 \\ 75 - 75 = 0 \\ 0 = 0$

$3( - \frac{1}{3} )^{2} - 14( - \frac{1}{3}) - 5 = 0 \\ 3( \frac{1}{9} ) + \frac{14}{3} - 5 = 0 \\ \frac{1}{3} + \frac{14}{3} - \frac{15}{3} = 0 \\ \frac{15}{3} - \frac{15}{3} = 0 \\ 0 = 0$

The equation is true for both roots.

<u>Answer</u>

$\large \boxed {3 {x}^{2} - 14x - 5 = 0}$

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2 years ago