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3 years ago

Please help. Algebra.

Mathematics

1 answer:

Tanya [424]3 years ago

6 0

Answer: The Answer is (A)

Step-by-step explanation: Have a brilliant day mate! - Lily ^-^

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When will the distance from A to B be negative?

Aneli [31]

The distance from A to B will be negative when the line is trending downward from left to right.

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3 years ago

A solid figure has 2 flat surfaces. 1 curved surface, no edges and no vertices. Name this soild figure

ikadub [295]

Answer:

cylinder

Step-by-step explanation:

the two flat surfaces are the circles on the top, and the curved surface is it's "body"

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3 years ago

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It's due in 20 minutes!!

slega [8]

Answer:

A. 18 sit-ups in one minute

B. 30 doors per hour

D. 18 words per minute

F. $30 per night

C. 3.5 miles per hour

E. $10.50 per pair of pants

Step-by-step explanation:

A. 36/2 = 18

B. 15 * 2 = 30

D. 72/4 = 18

F. 150/5 = 30

C. 10.5/3 = 3.5

E. 31.50/3 = 10.50

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3 years ago

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Prove the trigonometric identity

Annette [7]

Answer:

Proved See below

Step-by-step explanation:

Man this one is a world of its own :D Just a quick question are you a fellow Add Math student in O levels i remember this question from back in the day :D Anyhow Lets get started

For this question we need to know the following identities:

$1+tan^{2}x=sec^2x\\\\1+cot^2x=cosec^2x\\\\sin^2x+cos^2x=1$

Lets solve the bottom most part first:

$1-\frac{1}{1-sec^2x} \\\\$

Take LCM

$1-\frac{1}{1-sec^2x} \\\\\frac{1-sec^2x-1}{1-sec^2x} \\\\\frac{-sec^2x}{1-sec^2x} \\\\\frac{-(1+tan^2x)}{-tan^2x}$

now break the LCM

$\frac{-1}{-tan^2x}+\frac{-tan^2x}{-tan^2x}\\\\\frac{1}{tan^2x}+1\\\\cot^2x+1$

because 1/tan = cot x

and furthermore,

$cot^2x+1\\cosec^2x$

now we solve the above part and replace the bottom most part that we solved with $cosec^2x$

$\frac{1}{1-\frac{1}{cosec^2x} } \\\\\frac{1}{1-sin^2x} \\\\\frac{1}{cos^2x}\\\\sec^2x$

Hence proved! :D

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3 years ago

1. How many four-digit numbers have a digit sum of 3?

nika2105 [10]

Answer:

10 numbers

Step-by-step explanation:

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3 years ago