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Finger [1]
3 years ago
5

What is one thing that all polysaccharides have in common?

Chemistry
1 answer:
VashaNatasha [74]3 years ago
4 0
<h3><u>Answer</u>;</h3>

D. All polysaccharides are made up of carbon, hydrogen, and oxygen.

<h3><u>Explanation</u>;</h3>
  • A polysaccharide is a large molecule made of many monomers called monosaccharides such as glucose, galactose, fructose, etc.
  • Polysaccharides can be homopolysaccharides, where all monosaccharides are the same or heteropolysaccharide in which the monosaccharides vary.
  • They may be linear, where a molecule of polysaccharides has straight chain of monosaccharides, or branched polysaccharides in which a chain has arms.
  • <em><u>All polysaccharides contain oxygen, hydrogen and carbon atoms like all the carbohydrates.</u></em>

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H2SO4 + Ba(OH)2à BaSO4 + H2O is an unbalanced chemical equation. What is the coefficient for sulfuric acid (H2SO4) when this equ
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H₂SO₄ + Ba(OH)₂ -----> BaSO₄ + 2H₂O

Coefficient for sulfuric acid: 1
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If 81g of water is measured out, how many moles are in the sample? *
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3 years ago
What volume (in L) will a 32 g sample of butane gas, C4H10(g), occupy at a temperature of 45.0 oC and a pressure of 728 mm Hg?
larisa86 [58]

Answer:

15.0 L

Explanation:

To find the volume, you need to use the Ideal Gas Law:

PV = nRT

In this equation,

-----> P = pressure (mmHg)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas constant (62.36 L*mmHg/mol*K)

-----> T = temperature (K)

To calculate the volume, you need to (1) convert grams C₄H₁₀ to moles (via the molar mass), then (2) convert the temperature from Celsius to Kelvin, and then (3) calculate the volume (via the Ideal Gas Law).

Molar Mass (C₄H₁₀): 4(12.011 g/mol) + 10(1.008 g/mol)

Molar Mass (C₄H₁₀): 58.124 g/mol

32 grams C₄H₁₀              1 moles
-------------------------  x  -----------------------  = 0.551 moles C₄H₁₀
                                    58.124 grams

P = 728 mmHg                      R = 62.36 L*mmHg/mol*K

V = ? L                                    T = 45.0 °C + 273.15 = 318.15 K

n = 0.551 moles

PV = nRT

(728 mmHg)V = (0.551 moles)(62.36 L*mmHg/mol*K)(318.15 K)

(728 mmHg)V = 10922.7632

V = 15.0 L

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