All categories

3 years ago

Which point lies on the line with the point slope equation y-2=5 x-6

1 answer:

5 0

(y-y1) = m(x-x1)
y-2 = 5(x-6)

Therefore, point (x1,y1) lies on the line of equation
Therefore, point (6,2) lies on the line with the point slope equation y-2=5(x-6)

You might be interested in

A university found that of its students withdraw without completing the introductory statistics course. Assume that students reg

polet [3.4K]

Answer:

A university found that 30% of its students withdraw without completing the introductory statistics course. Assume that 20 students registered for the course.

a. Compute the probability that 2 or fewer will withdraw (to 4 decimals).

= 0.0355

b. Compute the probability that exactly 4 will withdraw (to 4 decimals).

= 0.1304

c. Compute the probability that more than 3 will withdraw (to 4 decimals).

= 0.8929

d. Compute the expected number of withdrawals.

= 6

Step-by-step explanation:

This is a binomial problem and the formula for binomial is:

$P(X = x) = nCx p^{x} q^{n - x}$

a) Compute the probability that 2 or fewer will withdraw

First we need to determine, given 2 students from the 20. Which is the probability of those 2 to withdraw and all others to complete the course. This is given by:

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 2) = 20C2(0.3)^2(0.7)^{18}\\P(X = 2) =190 * 0.09 * 0.001628413597\\P(X = 2) = 0.027845872524$

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 1) = 20C1(0.3)^1(0.7)^{19}\\P(X = 1) =20 * 0.3 * 0.001139889518\\P(X = 1) = 0.006839337111$

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 0) = 20C0(0.3)^0(0.7)^{20}\\P(X = 0) =1 * 1 * 0.000797922662\\P(X = 0) = 0.000797922662$

Finally, the probability that 2 or fewer students will withdraw is

$P(X = 2) + P(X = 1) + P(X = 0) \\= 0.027845872524 + 0.006839337111 + 0.000797922662\\= 0.035483132297\\= 0.0355$

b) Compute the probability that exactly 4 will withdraw.

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 4) = 20C4(0.3)^4(0.7)^{16}\\P(X = 4) = 4845 * 0.0081 * 0.003323293056\\P(X = 4) = 0.130420974373\\P(X = 4) = 0.1304$

c) Compute the probability that more than 3 will withdraw

First we will compute the probability that exactly 3 students withdraw, which is given by

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 3) = 20C3(0.3)^3(0.7)^{17}\\P(X = 3) = 1140 * 0.027 * 0.002326305139\\P(X = 3) = 0.071603672205\\P(X = 3) = 0.0716$

Then, using a) we have that the probability that 3 or fewer students withdraw is 0.0355+0.0716=0.1071. Therefore the probability that more than 3 will withdraw is 1 - 0.1071=0.8929

d) Compute the expected number of withdrawals.

E(X) = 3/10 * 20 = 6

Expected number of withdrawals is the 30% of 20 which is 6.

5 0

4 years ago

What is the answer for -8=s+6

9966 [12]

Answer:

s=-14

Step-by-step explanation:

-8 = s+6 Given

-14 = s Subtract 6 from both sides

7 0

3 years ago

Help please asap :)))

iVinArrow [24]

Answer:

Step-by-step explanation:

The volume is calculated like:

V= length* hauteur* wide

V= 5* 2 3/4* 10 1/2

$V= 5*\frac{11}{4} *\frac{21}{2} =\frac{5*11*21}{4*2} =\frac{1155}{8}=144.375 \\=144 \frac{3}{8} in^{3}$

3 0

3 years ago

Hello its me, the 6th grade crack head that needs help on a PEMDAS again! YAYY so anyways the question isssssss 10 divided by (3

Aneli [31]

Answer:

its 8...i think

Step-by-step explanation:

5 0

3 years ago

The width of a rectangular swimming pool is 16ft. The diagonal of the swimming pool is 34 ft. What is the length of the swimming

kobusy [5.1K]

The length of the swimming pool is 30 ft

5 0

3 years ago

Read 2 more answers