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alekssr [168]
4 years ago
12

Choose the correct simplification of the expression a^7b^8/a^4b^4

Mathematics
2 answers:
arsen [322]4 years ago
7 0
Move .Use the power rule to combine exponents.Add and to get .Move .Use the power rule to combine exponents.Add and to get .
Like...so it would get you:
(<span>a7</span><span>b12</span>)<span>(<span>a4</span><span>b8</span>)</span><span><span>(<span>a7</span><span>b12</span>)</span><span>(<span>a4</span><span>b8</span>)</span></span> Move <span><span>a4</span><span>a4</span></span> .<span><span><span>a4</span><span>a7</span><span>b12</span><span>b8</span></span><span><span>a4</span><span>a7</span><span>b12</span><span>b8</span></span></span> Use the power rule <span><span><span>am</span><span>an</span>=<span>a<span>m+n</span></span></span><span><span>am</span><span>an</span>=<span>a<span>m+n</span></span></span></span> to combine exponents.<span><span><span>a<span>4+7</span></span><span>b12</span><span>b8</span></span><span><span>a<span>4+7</span></span><span>b12</span><span>b8</span></span></span> Add <span>44</span> and <span>77</span> to get <span>1111</span> .<span><span><span>a11</span><span>b12</span><span>b8</span></span><span><span>a11</span><span>b12</span><span>b8</span></span></span> Move <span><span>b8</span><span>b8</span></span> .<span><span><span>a11</span><span>(<span>b8</span><span>b12</span>)</span></span><span><span>a11</span><span>(<span>b8</span><span>b12</span>)</span></span></span> Use the power rule <span><span><span>am</span><span>an</span>=<span>a<span>m+n</span></span></span><span><span>am</span><span>an</span>=<span>a<span>m+n</span></span></span></span> to combine exponents.<span><span>a11<span>b8+12</span></span><span>a11<span>b8+12</span></span></span> Add <span>88</span> and <span>1212</span> to get <span>2020</span> .<span><span><span>a11</span><span>b20</span></span><span><span>a11</span><span>b<span>20

So for the simplification, go with A, bc </span></span></span></span><span><span>a11<span>b8+12</span></span><span>a11<span>b8+12 looks the closest youre gong to get to whats there so A </span></span></span><span> a^11b^12 is yours.
~~~~Hope this helps!
</span>
Alex787 [66]4 years ago
4 0
The answer is B: a^3b^4<span>

Proof:
Simplify the following:
(a^7 b^8)/(a^4 b^4)

Combine powers. (a^7 b^8)/(a^4 b^4) = a^(7 - 4) b^(8 - 4):
a^(7 - 4) b^(8 - 4)

7 - 4 = 3:
a^3 b^(8 - 4)

8 - 4 = 4:
Answer:  a^3 b^4

PS: I just wish that you put the equation down as it's intended i.e.
a^7b^8/a^4b^4 is not the same as (<span>a^7b^8)/(a^4b^4)</span>
</span>
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