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3 years ago

4. The decomposition of N20s in the gas phase is first order in N20s. If the concentration of N2Os drops from

Chemistry

1 answer:

arsen [322]3 years ago

4 0

Answer:

42.5 mins

Explanation:

Given that for a first order reaction;

ln[A] = ln[A]o - kt

[A] = 0.1 M

[A]o = 0.2 M

t= 14.2 mins

ln0.1 = ln0.2 - 14.2t

ln0.1 - ln0.2/-14.2=k

k= -2.303 -(-1.609)/-14.2

k= 0.0489 min-1

So;

ln0.025 =ln0.2 - 0.0489t

ln0.025 - ln0.2/-0.0489 =t

t= -3.689 - (-1.609)/-0.0489

t= 42.5 mins

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The concentration of copper(II) sulfate in one brand of soluble plant fertilizer is 0.070% by weight. If a 21.5 g sample of this

Semmy [17]

Answer:

The molar concentration of $Cu^{2+}$ ions in the given amount of sample is $4.73\times 10^{-5}M$

Explanation:

Given that,

Mass of sample = 21.5 g

0.07 % (m/m) of copper (II) sulfate in plant fertilizer

This means that, in 100 g of plant fertilizer, 0.07 g of copper (II) sulfate is present

So, in 20 g of plant fertilizer

, $=\frac{0.07}{100}\times 21.5}\\=0.0151g$ of copper (II) sulfate is present.

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

Mass of solute (copper (II) sulfate) = 0.0151 g

Molar mass of copper (II) sulfate = 159.6 g/mol

Volume of solution = 2.0 L

$\text{Molarity of solution}=\frac{0.0151g}{159.6g/mol\times 2.0L}\\\\\text{Molarity of solution}=4.73\times 10^{-5}M$

The chemical equation for the ionization of copper (II) sulfate follows:

$CuSO_4\rightarrow Cu^{2+}+SO_4^{2-}$

1 mole of copper (II) sulfate produces 1 mole of copper (II) ions and sulfate ions

Molarity of copper (II) ions = $4.73\times 10^{-5}M$

Hence, the molar concentration of $Cu^{2+}$ ions in the given amount of sample is $4.73\times 10^{-5}M$

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3 years ago

Balance the following chemical equation: C2H60+02 → CO2 + H20

pantera1 [17]

Answer:

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Credit goes to "Erin M" answered on yahoo answers a decade ago.

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3 years ago

Bacteria consume other organisms for food, making them heterotrophs. True or False?

11111nata11111 [884]

Answer:

I would say true!

Explanation:

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3 years ago

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