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timurjin [86]
2 years ago
9

4. The decomposition of N20s in the gas phase is first order in N20s. If the concentration of N2Os drops from

Chemistry
1 answer:
arsen [322]2 years ago
4 0

Answer:

42.5 mins

Explanation:

Given that for a first order reaction;

ln[A] = ln[A]o - kt

[A] = 0.1 M

[A]o = 0.2 M

t= 14.2 mins

ln0.1 = ln0.2 - 14.2t

ln0.1 - ln0.2/-14.2=k

k= -2.303 -(-1.609)/-14.2

k= 0.0489 min-1

So;

ln0.025 =ln0.2 - 0.0489t

ln0.025 - ln0.2/-0.0489 =t

t= -3.689 - (-1.609)/-0.0489

t= 42.5 mins

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To remove one electron from singly ionized helium, will require approximately 54.4 eV or 8.72 1020 J of energy.

The amount of energy required by an isolated, gaseous molecule in the electronic state of the ground to absorb in order to discharge an electron and produce a cation has been known as the ionization energy. The amount of energy required for every atom in a mole to drop one electron is most often given as kJ/mol.

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Summarize the relationship between an electron's energy level and its location in an atom
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A scientist measures the standard enthalpy change for the following reaction to be 67.9 kJ:
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Answer:

-252.5 kJ/mol = ΔH H2O(g)

Explanation:

ΔH Fe2O3 = -825.5kJ/mol

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Based on Hess's law, ΔH of a reaction is the sum of ΔH of products - ΔH of reactants. For the reaction:

Fe2O3(s) + 3 H2(g) →2Fe(s) + 3 H2O(g)

ΔHr = 67.9kJ/mol = 3*ΔH H2O + 2*ΔHFe - (ΔH Fe2O3 + 3*Δ H2)

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67.9 = 3*ΔH H2O(g) + 825.5kJ/mol

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<h3>-252.5 kJ/mol = ΔH H2O(g)</h3>
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