Question

8.23 moles of mercury (II) oxide reacts with 7.90 moles of carbon monoxide to produce carbon dioxide and mercury. Determine the moles of mercury which could be produced? - HELP

Answer 1

7.9moles of Hg

Explanation:

Given parameters:

Number of moles of HgO = 8.23moles

Number of moles of CO = 7.90moles

Unknown:

Number of moles of Hg produced = ?

Solution:

To solve this problem, we work from the known to the unknown substance. Here we will use the limiting reagent to determine the amount of product that is being formed.

The limiting reagent is the one in short supply in the reaction;

  Reaction equation;

 

         HgO + CO → Hg + CO₂

The reaction above is balanced with respect to the number of atoms

Now we need to determine the limiting reagent;

  In the reaction;

   1 mole of HgO reacts with 1 mole of CO

  8.23 mole of HgO will require 8.23 mole of CO

but we were given 7.9 mole of CO. This is the limiting reagent and it will determine the extent of the reaction.

Therefore;

   I mole of CO will produce 1 mole of Hg

  7.9moles of CO will produce 7.9moles of Hg

learn more:

Number of moles brainly.com/question/1841136

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