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aliina [53]
3 years ago
15

8.23 moles of mercury (II) oxide reacts with 7.90 moles of carbon monoxide to produce carbon dioxide and mercury. Determine the

moles of mercury which could be produced? - HELP
Chemistry
1 answer:
Verdich [7]3 years ago
7 0

7.9moles of Hg

Explanation:

Given parameters:

Number of moles of HgO = 8.23moles

Number of moles of CO = 7.90moles

Unknown:

Number of moles of Hg produced = ?

Solution:

To solve this problem, we work from the known to the unknown substance. Here we will use the limiting reagent to determine the amount of product that is being formed.

The limiting reagent is the one in short supply in the reaction;

  Reaction equation;

 

         HgO + CO → Hg + CO₂

The reaction above is balanced with respect to the number of atoms

Now we need to determine the limiting reagent;

  In the reaction;

   1 mole of HgO reacts with 1 mole of CO

  8.23 mole of HgO will require 8.23 mole of CO

but we were given 7.9 mole of CO. This is the limiting reagent and it will determine the extent of the reaction.

Therefore;

   I mole of CO will produce 1 mole of Hg

  7.9moles of CO will produce 7.9moles of Hg

learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

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Fynjy0 [20]

The quantity of carbon tetrachloride, CCl₄ she will use to make her conversion is molar mass

<h3>Description of mole </h3>

The mole of a substance is related to it's mass and molar mass according to the following equation:

Mole = mass / molar mass

<h3>How to determine the mole of CCl₄</h3>
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  • Mole of CCl₄ =?

Mole = mass / molar mass

Mole of CCl₄ = 150 / 154

Mole of CCl₄ = 0.974 mole

Thus, we can see that the molar mass of CCl₄ is needed to obtain the number of mole.

Learn more about mole:

brainly.com/question/13314627

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