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aliina [53]
3 years ago
15

8.23 moles of mercury (II) oxide reacts with 7.90 moles of carbon monoxide to produce carbon dioxide and mercury. Determine the

moles of mercury which could be produced? - HELP
Chemistry
1 answer:
Verdich [7]3 years ago
7 0

7.9moles of Hg

Explanation:

Given parameters:

Number of moles of HgO = 8.23moles

Number of moles of CO = 7.90moles

Unknown:

Number of moles of Hg produced = ?

Solution:

To solve this problem, we work from the known to the unknown substance. Here we will use the limiting reagent to determine the amount of product that is being formed.

The limiting reagent is the one in short supply in the reaction;

  Reaction equation;

 

         HgO + CO → Hg + CO₂

The reaction above is balanced with respect to the number of atoms

Now we need to determine the limiting reagent;

  In the reaction;

   1 mole of HgO reacts with 1 mole of CO

  8.23 mole of HgO will require 8.23 mole of CO

but we were given 7.9 mole of CO. This is the limiting reagent and it will determine the extent of the reaction.

Therefore;

   I mole of CO will produce 1 mole of Hg

  7.9moles of CO will produce 7.9moles of Hg

learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

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Calculate the mass in grams of 8.35 × 1022 molecules of CBr4.
antiseptic1488 [7]

Answer: 45.983 g CBr₄

Explanation:

To convert from moles to grams, you know that we will need molar mass and Avogadro's number.

Avogadro's number: 6.022×10²³ molecules/mol

Molar mass: 331.627 grams/mol

Now that we have what we need, you can use these to solve for grams. 8.35*10^2^2molecules CBr_{4} *\frac{1mol}{6.022*10^2^3molecules} *\frac{331.627 g}{1 mol} =45.983 g

Our final answer is 45.983 g CBr₄.

4 0
3 years ago
How many grams of KOH do we need to make 250.0ml of a 0.75 M
ZanzabumX [31]

Answer:

10.52g KOH

Explanation:

250.0 ml X 1L/1000ml X 0.75 mol KOH/1L X 56.105gKOH/1 mol KOH =10.52g KOH

5 0
3 years ago
According to 2011/Chemistry Reference Tables
Phoenix [80]

Answer:

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Explanation:

C. The electronegativity value of calcium is lower than the electronegativity value of silicon

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4 0
3 years ago
A sample of gas occupies 9.0 mL at a pressure of 500.0 mm Hg. A new volume of the same sample is at a pressure of 750.0 mm Hg.
Anuta_ua [19.1K]
<h3>Answer:</h3>

                The New pressure (750 mmHg) is greater than the original pressure (500 mmHg) hence, the new volume (6.0 mL) is smaller than the original volume (9.0 mL).

<h3>Solution:</h3>

              According to Boyle's Law, " <em>The Volume of a given mass of gas at constant temperature is inversely proportional to the applied Pressure</em>". Mathematically, the initial and final states of gas are given as,

                                     P₁ V₁  =  P₂ V₂    ----------- (1)

Data Given;

                  P₁  =  500 mmHg

                  V₁  =  9.0 mL

                  P₂  =  750 mmHg

                  V₂  =  ??

Solving equation 1 for V₂,

                   V₂  =  P₁ V₁ / P₂

Putting values,

                   V₂  =  (500 mmHg × 9.0 mL) ÷ 750 mmHg

                   V₂  =  6.0 mL

<h3>Result:</h3>

            The New pressure (750 mmHg) is greater than the original pressure (500 mmHg) hence, the new volume (6.0 mL) is smaller than the original volume (9.0 mL).

4 0
3 years ago
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Calculate the molarity of 22.5 g of MgS in 829 mL of solution
krek1111 [17]

Answer:18652.5

Explanation

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