Each ream weighs 5 lb . so, reducing 10 lb means removing 2 reams from the 12. so, how do we arrange the 10 reams so that its easy to carry?
i thinks that 3 stacks will not work as it wont be a symmetric arrangement as 1 will be left out. So, 2 stacks of 5 each would be easy to carry. but the stacks should be placed in such a way that the lengths are parallel to each other and not in-line which would increase the length making it comparatively longer. its easier to hold a (2*8.5,11,2*5=17,11,17)compact box.
Answer:
Simplify -> 16^z + 2^1+6z - 2
Step-by-step explanation:
Answer:
9 + 22h
Explanation:
The question is incomplete as Gordon's height is not given. To solve further, we will represent this height with h
So, we have:
nine more than the 
of 22 and 
More than, in this case means plus (+)
nine + the of 22 and
Rewrite nine as 9 and substitute h for Gordons height
9 + the of 22 and h
product, in this case means multiplication (*)
9 + 22 * h
So, the expression is:
9 + 22h
