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Marta_Voda [28]
3 years ago
10

Plzzz help I’m being timed!!!

Mathematics
2 answers:
vichka [17]3 years ago
8 0

Answer:

W

Step-by-step explanation:

quadrant 4 is the bottom right one

BartSMP [9]3 years ago
7 0

W: 4;5

V: 4;2

Y: -1;2

X: -5;-1

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A weather forecaster predicts that there is a 45% probability of snow today. What is the probability that it will not snow?
Ilia_Sergeevich [38]
55% if the percent is out of 100%. in which most weather statisics are out of 100. in which you take 100-45= giving you 55%
8 0
3 years ago
The mean weight of an adult is 69 kilograms with a variance of 121. If 31 adults are randomly selected, what is the probability
amid [387]

Answer:

0.2236 = 22.36% probability that the sample mean would be greater than 70.5 kilograms.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Also, important to remember that the standard deviation is the square root of the variance.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 69, \sigma = \sqrt{121} = 11, n = 31, s = \frac{11}{\sqrt{31}} = 1.97565

What is the probability that the sample mean would be greater than 70.5 kilograms?

This is 1 subtracted by the pvalue of Z when X = 70.5. So

Z = \frac{X - \mu}{\sigma}

By the Central limit theorem

Z = \frac{X - \mu}{s}

Z = \frac{70.5 - 69}{1.97565}

Z = 0.76

Z = 0.76 has a pvalue of 0.7764

1 - 0.7764 = 0.2236

0.2236 = 22.36% probability that the sample mean would be greater than 70.5 kilograms.

8 0
3 years ago
Number of subsets of B={p,q,r}​
oksian1 [2.3K]

Answer:

Step-by-step explanation:

B = {p , q , r}

Number of subsets = 2^{n}

Her, n  is the number of elements in the set.

Number of subsets = 2³ = 8

3 0
3 years ago
Your friend is graphing the point (4, 3). She plans to start at the origin and go up 4 spaces. Which statement about her method
goldfiish [28.3K]
The true statement about her method would be to start at the origin. But you would go up 4 spaces you would go to the right 4 spaces.
7 0
3 years ago
Read 2 more answers
1) 0.52 + 1.6 + 8.26 =
Nadya [2.5K]

Step-by-step explanation:

1 10.38

2 16.77

3 11.499

4 11.486

5 0.0947

6 30.52875

7 525

8 32.57862069

9 16.5625

5 0
2 years ago
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