It is true that the product of two consecutive even integers are always one less than the square of their average.
<u>Step-by-step explanation</u>:
Let the two consecutive odd integers be 1 and 3.
- The product of 1 and 3 is (1
3)=3 - The average of 1 and 3 is (1+3)/2 =4/2 = 2
- The square of their average is (2)² = 4
∴ The product 3 is one less than the square of their average 4.
Let the two consecutive even integers be 2 and 4.
- The product of 2 and 4 is (2
4)=8 - The average of 2 and 4 is (2+4)/2 =6/2 = 3
- The square of their average is (3)² = 9
∴ The product 8 is one less than the square of their average 9.
Thus, It is true that the product of two consecutive even integers are always one less than the square of their average.
Answer:
285
Step-by-step explanation:
use algebra
third is x
second is 4x
first is 4x-3
x+4x+4x-3
9x-3 = x+x+1+x+2
9x-3=3x+3
12x=6, divide x=2
third is 2, sec is 8, first is 5
Answer:
64°
Step-by-step explanation:
First, we have to find the angle situated in R, the addition of all angles in a triangle is 180° so that means:
x + 68 + 48 = 180
x = 180-116 = 64°
Now, remember that this angle (64°) is the same as this one = ?, thanks to one property.
So basically, that angle has the same value as that one.
? = 64°
Hope it was helpful ;)
Answer:
a: 1/12
b: 1/6
c: 1/2
d: 1/2
e: 1/12
f: 1/3
Step-by-step explanation:
Answer:
False
Step-by-step explanation:
The slope is not constant