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Tpy6a [65]
2 years ago
8

Which structure is the arrow pointing to? What is the function of this organelle?

Chemistry
2 answers:
Vesnalui [34]2 years ago
8 0

Explanation:

<h3>1.) The arrow pointing to the nucleus. A cell is the smallest unit in an organism.</h3><h3>2.) The nucleus controls and regulates the activities of the cells and carries the genes, structures that contain the hereditary information.</h3>
STatiana [176]2 years ago
7 0

answer 1. The arrow is pointing to the "nucleus."

Explanation:

A cell is the smallest unit in an organism. It mainly functions to provide structure to the human body, thus it is called "the building blocks of life."

There are 6 organelles in a cell and these are Nucleus, Ribosomes, Endoplasmic Reticulum, Golgi Apparatus, Chloroplasts, and Mitochondria.

The arrow is pointing to the cell's nucleus in the image above. This is an organelle that is enclosed in a membrane. It is where you can find the deoxyribonucleic acid or the DNA, which is essential for hereditary function. It also coordinates activities in the cell, such as metabolism, synthesis of proteins, cell division.

Remember, not all cells have a nucleus. Only eukaryotic cells have a nucleus. These cells are considered more advanced.

2. An organelle is a subcellular structure that has one or more specific jobs to perform in the cell, much like an organ does in the body. Among the more important cell organelles are the nuclei, which store genetic information; mitochondria, which produce chemical energy; and ribosomes, which assemble proteins.

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When all colors are absorbed, you see:<br><br> black<br> white<br> green<br> yellow
wolverine [178]

uhmm, white.

Explanation:

you'll basically look like blind ig

5 0
3 years ago
The equilibrium constant, Kp, for the following reaction is 0.497 at 500K.PCl5(g) PCl3(g) + Cl2(g)If an equilibrium mixture of t
Anestetic [448]

<u>Answer:</u> The equilibrium partial pressure of chlorine gas is 0.360 atm

<u>Explanation:</u>

For the given chemical equation:

PCl_5(g)\rightleftharpoons PCl_3(g)+Cl2(g)

The expression of K_p for above reaction follows:

K_p=\frac{p_{Cl_2}\times p_{PCl_3}}{p_{PCl_5}}

We are given:

K_p=0.497\\p_{PCl_3}=0.651atm\\p_{PCl_5}=0.471atm

Putting values in above equation, we get:

0.497=\frac{p_{Cl_2}\times 0.651}{0.471}\\\\p_{Cl_2}=0.360atm

Hence, the equilibrium partial pressure of chlorine gas is 0.360 atm

5 0
3 years ago
What happens to the sugars that are made during photosynthesis?
KiRa [710]
The sugars (c6h12o6) or the glucose that is made during photosynthesis is turned into glucose cellulose or starch that the plant can use for energy and food for the plant. Hope this helps.
8 0
3 years ago
Consider the reaction: 2 SO2(g) + O2(g) &lt;----&gt; 2 SO3. If, at equilibrium at a certain temperature, [SO2] = 1.50 M, [O2] =
vlada-n [284]

Answer:

5.79

Explanation:

The following data were obtained from the question:

Concentration of SO2, [SO2] = 1.50 M

Concentration of O2, [O2] = 0.120 M

Concentration of SO3, [SO3] = 1.25 M

Equilibrium constant, (K) =..?

The balanced equation for the reaction is given below:

2SO2(g) + O2(g) <==> 2SO3(g)

From the balanced equation, the equilibrium constant K is written as follow:

K = [SO3]²/ [SO2]²• [O2]

With the above, the value of the equilibrium constant, K can be obtained as follow

K = [SO3]²/ [SO2]²• [O2]

K = (1.25)² / (1.50)² × 0.120

K = 1.5625 / ( 2.25 x 0.120)

K = 5.79

Therefore, the equilibrium constant is 5.79.

7 0
3 years ago
The vapor pressure of water is 1.00 atm at 373 K, and the enthalpy of vaporization is 40.68 kJ mol!. Estimate the vapor pressure
Yuki888 [10]

Answer:

The vapor pressure at temperature 363 K is 0.6970 atm

The vapor pressure at 383 K is 1.410 atm

Explanation:

To calculate \Delta H_{vap} of the reaction, we use clausius claypron equation, which is:

\ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

P_1 = vapor pressure at temperature T_1

P_2 = vapor pressure at temperature T_2

\Delta H_{vap} = Enthalpy of vaporization  

R = Gas constant = 8.314 J/mol K

1) \Delta H_{vap}=40.68 kJ/mol=40680 J/mol

T_1 = initial temperature =363 K

T_2 = final temperature =373 K

P_2=1 atm, P_1=?

Putting values in above equation, we get:

\ln(\frac{1 atm}{P_1})=\frac{40680 J/mol}{8.314J/mol.K}[\frac{1}{363}-\frac{1}{373}]

P_1=0.69671 atm \approx 0.6970 atm

The vapor pressure at temperature 363 K is 0.6970 atm

2) \Delta H_{vap}=40.68 kJ/mol=40680 J/mol

T_1 = initial temperature =373 K

T_2 = final temperature =383 K

P_1=1 atm, P_2?

Putting values in above equation, we get:

\ln(\frac{P_2}{1 atm})=\frac{40680 J/mol}{8.314J/mol.K}[\frac{1}{373}-\frac{1}{383}]

P_2=1.4084 atm \approx 1.410 atm

The vapor pressure at 383 K is 1.410 atm

8 0
3 years ago
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