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rosijanka [135]
3 years ago
5

Which of the following is most appropriate in measuring the mass of a cow; kilogram, gram or meter? Explain your answer with det

ail. PLZZZZ help me with this one!
Chemistry
2 answers:
Blababa [14]3 years ago
7 0
The most appropriate unit to take the weight of a cow would be kilograms.

Meters are a unit of distance and are not applicable here
A gram is too small to use in this instance
goldfiish [28.3K]3 years ago
5 0
Kilogram is the appropriate one.
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Electrons are electrochemically negatively charged particles that move random around the nucleus. They have a relatively small mass compared to Protons and Neutrons. They are found in electron clouds that surround the nucleus and their movement and properties provide for the bonding characteristics of each atom.
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In the reaction of 675.9 grams of barium chloride and excess silver(I) nitrate, how many grams of silver(I) chloride should get
zvonat [6]

Taking into account the reaction stoichiometry, the mass of silver(I) chloride formed is 930.37 grams.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 AgNO₃ + BaCl₂ → 2 AgCl + Ba(NO₃)₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • AgNO₃: 2 moles
  • BaCl₂: 1 mole
  • AgCl: 2 moles
  • Ba(NO₃)₂: 1 mole

The molar mass of the compounds is:

  • AgNO₃: 169.87 g/mole
  • BaCl₂: 208.24 g/mole
  • AgCl: 143.32 g/mole
  • Ba(NO₃)₂: 261.34 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

AgNO₃: 2 moles ×169.87 g/mole= 339.74 grams

BaCl₂: 1 mole ×208.24 g/mole= 208.24 grams

AgCl: 2 moles ×143.32 g/mole= 286.64 grams

Ba(NO₃)₂: 1 mole×261.34 g/mole= 261.34 grams

<h3>Mass of silver(I) chloride formed</h3>

The following rule of three can be applied:  if by reaction stoichiometry 208.24 grams of barium chloride form 286.64 grams of silver(I) chloride, 675.9 grams of barium chloride form how much mass of silver(I) chloride?

mass of silver(I) chloride=\frac{675.9 grams of barium chloride x286.64 grams of silver(I) chloride }{208.24 grams of barium chloride}

mass of silver(I) chloride= 930.37 grams

Finally, the mass of silver(I) chloride formed is 930.37 grams.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

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Write the name of flame used In charcoal cavity test.why?
Kryger [21]

Answer:

the reducing flame also called the carburizing flame.

Explanation:

because it gets the oxides of the unknown salts

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