On a ceiling, there were tiny droplets of blood less than 1 mm in diameter. the victim was lying in a pool of blood. no other ma
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Answer :
(a) The given number in 2 significant figures will be,
(b) The given number in 4 significant figures will be,
(c) The given number in 3 significant figures will be,
Explanation :
Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.
(a) The given number 00003554 converted into 2 significant figures.
In 00003554, there are 4 significant figures. Now we have to convert it into 2 significant figures.
The given number in 2 significant figures will be,
(b) The given number 35.8348 converted into 4 significant figures.
In 35.8348, there are 6 significant figures. Now we have to convert it into 4 significant figures.
The given number in 4 significant figures will be,
(c) The given number 22.4555 converted into 3 significant figures.
In 22.4555, there are 6 significant figures. Now we have to convert it into 3 significant figures.
The given number in 3 significant figures will be,
Answer: The empirical formula for the given compound is
Explanation:
The chemical equation for the combustion of compound having carbon, hydrogen, and nitrogen follows:
where, 'x', 'y' and 'z' are the subscripts of carbon, hydrogen and nitrogen respectively.
We are given:
Mass of
Mass of
We know that:
Molar mass of carbon dioxide = 44 g/mol
Molar mass of water = 18 g/mol
For calculating the mass of carbon:
In 44 g of carbon dioxide, 12 g of carbon is contained.
So, in 21363 g of carbon dioxide, of carbon will be contained.
For calculating the mass of hydrogen:
In 18 g of water, 2 g of hydrogen is contained.
So, in 6125 g of water, of hydrogen will be contained.
Now we have to calculate the mass of nitrogen.
Mass of nitrogen in the compound = (7875) - (5826.27 + 680.55) = 1368.18 g
To formulate the empirical formula, we need to follow some steps:
Step 1: Converting the given masses into moles.
Moles of Carbon =
Moles of Hydrogen =
Moles of Nitrogen =
Step 2: Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0154 moles.
For Carbon =
For Hydrogen =
For Nitrogen =
Step 3: Taking the mole ratio as their subscripts.
The ratio of C : H : N = 5 : 7 : 1
Hence, the empirical formula for the given compound nicotine is