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KIM [24]
3 years ago
7

What class of organic product results when 1-heptyne is reacted with disiamylborane followed by treatment with basic hydrogen pe

roxide?
Chemistry
1 answer:
yuradex [85]3 years ago
3 0

Answer:

aldehyde

Explanation:

Aldehydes are a large class of reactive organic compounds (R-CHO) having a carbonyl functional group attached to one hydrocarbon radical and a hydrogen atom.

So, when terminal alkynes, for example, 1-heptyne react on Hydroboration oxidation(i.e. disiamylborane followed by treatment with basic hydrogen peroxide), the formation of aldehyde occurs.

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The diameter of a sphere is 4 centimeters. Which represents the volume of the sphere?
pishuonlain [190]

Answer:

V=25.133 cm^3

(Is 4 the diameter you were given? To get one of those answers, I think you May have put the wrong diameter)

Explanation:

Radius is diameter/2

R=4/2

R=2

Volume of a sphere=4/3πr3

V=4/3π(2)3

V=25.133 cm^3

7 0
3 years ago
Which atom attracts electrons more strongly?
lesya [120]
Bromine attracts electrons more strongly. Cesium is In fact the least electro negative element.

Sodium is more likely to lose an electron because is is less electro negative. Strong electronegativity make the element want more electrons. Sodium has loose electrons with a lower electronegativity so it gives it up easier.
3 0
4 years ago
Read 2 more answers
Knowledge of the functioning of cells and DNA has led to the creation of new life in laboratories. What is an example of an ethi
ziro4ka [17]

Answer:

Explanation:

It’s D

3 0
3 years ago
Imagine that you have a 5.00 LL gas tank and a 4.50 LL gas tank. You need to fill one tank with oxygen and the other with acetyl
Otrada [13]

Answer:

P_2=139atm

Explanation:

Hello,

In this case, even we are given two different gases, as it says "ensure that you run out of each gas at the same time", they shall behave as only one, for that reason, no matter the amounts, they are going to be modeled by means of the Boyle's law, as temperature remains unchanged, which allows us to understand the pressure-volume behavior as an inversely proportional relationship:

P_1V_1=P_2V_2

Hence, we solve for the P2, representing the pressure of the acetylene as shown below:

P_2=\frac{P_1V_1}{V_2} =\frac{5.00L*125atm}{4.50L} \\\\P_2=139atm

Best regards.

6 0
3 years ago
Read 2 more answers
The breakdown of a certain pollutant X in sunlight is known to follow first-order kinetics. An atmospheric scientist studying th
a_sh-v [17]

Explanation:

Change in the concentration of reactant that is consumed in per unit time is known as rate of reaction.

The given chemical reaction will be written as follows.

            X \overset{sunlight}{\rightarrow} Pdt

Hence, rate law for the given reaction will be as follows.

                   Rate = kP_{x}

where,           k = rate constant

                P_{x} = initial pressure of the pollutant X

It is given that, P_{i} =  initial partial pressure of X = 0.473 atm

                        P_{f} =  final partial pressure of X = 0.376 atm

                         Time = 5.6 hours

Hence, formula for rate constant of first order reaction is as follows.

                k = \frac{1}{t} ln(\frac{P_{i}}{P_{f}}

                   = \frac{1}{5.6} ln(\frac{0.473}{0.376})

                   = 0.041 per hour

Therefore, rate of decomposition will be calculated as follows.

              Rate = \frac{dP}{dt} = kP_{i}

                       = 0.041 hr^{-1} \times 0.473 atm

                       = 0.019 atm hr^{-1}

Thus, we can conclude that initial rate of decomposition of X is 0.019 atm hr^{-1}.

7 0
3 years ago
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