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Drupady [299]
2 years ago
12

Can someone tell me the answer to this please this is mad confusing

Mathematics
1 answer:
torisob [31]2 years ago
5 0

Answer:

12

Step-by-step explanation:

Assume that those angles' curve in the triangle have same measure.

Law of Sin states that:

\displaystyle \large{ \frac{ \sin A}{a} =  \frac{ \sin B}{b}   =  \frac{ \sin C}{c} = 2R}

From the question, assume that B and C are congruent or have same measure. Let B and C be congruent; angle B = angle C thus:-

\displaystyle \large{ \frac{ \sin B}{b}   =  \frac{ \sin C}{c} } \\ \displaystyle \large{ \frac{ \sin B}{b}   =  \frac{ \sin B}{c} }

Let b = x and c = 12; for angle B, it's not given so leave it.

\ \displaystyle \large{ \frac{ \sin B}{x}   =  \frac{ \sin B}{12} }

Multiply both sides by LCM which is 12x.

\ \displaystyle \large{ \frac{ \sin B}{x}(12x)   =  \frac{ \sin B}{12}(12x) }  \\  \ \displaystyle \large{12\sin B =\sin Bx  }

Divide both sides by sinB.

\displaystyle \large{ \frac{12\sin B}{\sin B}   = \frac{\sin Bx }{ \sin B}} \\    \displaystyle \large{ 12 = x}

Therefore, x = 12.

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Marlene rides her bike at a rate of 16 miles per hour. The time in hours that she rides is represented by the variable t, and th
Vesna [10]

Question is Incomplete; Complete question is given below;

Marlene rides her bike at a rate of 16 miles per hour. The time in hours that she rides is represented by the variable t, and the distance she rides is represented by the variable d. Which statements are true of the scenario? Check all that apply.

a. The independent variable, the input, is the variable d, representing distance.

b. The distance traveled depends on the amount of time Marlene rides her bike.

c. The initial value of the scenario is 16 miles per hour.

d. The equation t = d + 16 represents the scenario.

e. The function f(t) = 16t represents the scenario.

Answer:

OPTION (b) and (e) are the true statements.

Step-by-step explanation:

Given:

t=> time in hours that she rides

d=>  distance she rides

We have to find the statements that are true of the scenario.

Solution:

d=16t

The equation itself is a linear equation which presents an equation's scenario and time (t) is a independent variable and distance (d) is a dependent variable.

Equation for distance according to function is  f(t)=16t

Here, we can use graph tool, you can see the attested image below.

Function's domain is the interval⇒ [0,∞)

t\geq0

Function's range is the interval⇒ [0,∞)

f(t)\geq0

The statements which are TRUE are explained below :

b) The distance traveled depends on the amount of time Marlene rides her bike

It is true because as explained above that equation for distance according to function is  f(t)=16t

e) The function f(t) = 16t represents the scenario.

It is true because as explained that the scenario has been represented by the function above that f(t)=16t

* The statement (a) is false because the variable t is the independent variable.

* The statement (c) is false because 16 is been represented as the slope or the rate of the linear equation.

* The statement (d) is false because t = d + 16 donot represents the scenario.

8 0
3 years ago
-1/6 x -2 1/10 = ?<br> help ya girl out
Nataly_w [17]

Answer:

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Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Help please.................
olganol [36]

Answer:

(-4, 0) and (5/2, 0)

Step-by-step explanation:

if you graph the equation you can see where the curve intersects the x-axis or you can factor the equation into:  (2x - 5)(x + 4) = 0

set each factor equal to zero and solve:

2x - 5 = 0

2x = 5

x = 5/2

x + 4 = 0

x = -4

6 0
2 years ago
If the distance traveled is (4s3 - 6s² + 4s + 14) miles and the rate is (s + 1) mph, write an expression, in hours, for the time
BartSMP [9]

The equation for time is URM:

time =  \frac{distance}{speed \: (rate)}

t(s) =  \frac{4s {}^{3}  - 6s {}^{2}  + 4s + 14}{s + 1}  =  \frac{2(s + 1)(2s {}^{2} - 5s + 7) }{s + 1}  \\  t(s) = 2(2s {}^{2}  - 5s + 7) \\ t(s) = 4s {}^{2}  - 10s + 14

3 0
1 year ago
Use the rules of exponents to simplify the expressions. Match the expression with its equivalent value.
Lelechka [254]

Answer:

1) \frac{(-2)^{-5}}{(-2)^{-10}}=-32

2) 2^{-1}.2^{-4} = \frac{1}{32}

3) (-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}

4) \frac{2}{2^{-4}} = 32

Step-by-step explanation:

1) \frac{(-2)^{-5}}{(-2)^{-10}}

Solving using exponent rule: a^{-m}=\frac{1}{a^m}

\frac{(-2)^{-5}}{(-2)^{-10}}\\=(-2)^{-5+10}\\=(-2)^{5}\\=-32

So, \frac{(-2)^{-5}}{(-2)^{-10}}=-32

2) 2^{-1}.2^{-4}

Using the exponent rule: a^m.a^n=a^{m+n}

We have:

2^{-1}.2^{-4}\\=2^{-1-4}\\=2^{-5}

We also know that: a^{-m}=\frac{1}{a^m}

Using this rule:

2^{-5}\\=\frac{1}{2^5}\\=\frac{1}{32}

So, 2^{-1}.2^{-4} = \frac{1}{32}

3) (-\frac{1}{2} )^3.(-\frac{1}{2} )^2

Solving:

(-\frac{1}{2} )^3.(-\frac{1}{2} )^2\\=(-\frac{1}{8} ).(\frac{1}{4} )\\=-\frac{1}{32}

So, (-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}

4) \frac{2}{2^{-4}}

We know that: a^{-m}=\frac{1}{a^m}

\frac{2}{2^{-4}}\\=2\times 2^4\\=2(16)\\=32

So, \frac{2}{2^{-4}} = 32

3 0
3 years ago
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