Answer:
The velocity of the car after the collision is -5.36 m/s
Step-by-step explanation:
An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.
let the following:
m₁ = mass of the car = 1400 kg
m₂ = mass of the truck = 3200 kg
u₁ = velocity of the car before collision = 13.7 m/s
u₂ = velocity of the truck before collision = 0 m/s
v₁ = velocity of the car after collision
v₂ = velocity of the truck after collision
v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)
= [ 13.7 * (1400 - 3200) + 0 * 2 * 3200 ]/ (1400 + 3200)
= - 5.36 m/s
So, <u>the velocity of the car after the collision is -5.36 m/s</u>
Answer:
first answer:-1.75
second:-15.75
third:-40.25
Step-by-step explanation:i am too lazy srry
Answer: The first.
Step-by-step explanation: If you draw out a triangle and lable the points on each point with values from each triangle, you get J=M, K=N, and L=O. The first is the only one that proves it.
I=PRT
I=interest
P=initial amount
R=rate in decimal
T=time in years
given
P=5523
R=4.99%=0.0499
T=7
I=(5523)(0.0499)(7)
I=1929.1839
round
$1929.18 interest earned
Answer:
Step-by-step explanation:
(6x+1)4 = 124
6x+1 = 31
x = 5
