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2 years ago

PLEASE HELP I NEED THIS ASAP I WILL MARK YOU THE TOP!!!!

Mathematics

1 answer:

GalinKa [24]2 years ago

4 0

Answer:

for the first one

Step-by-step explanation:

you would add 9 to each side making x= a negative number

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A store down the street is selling a bicycle for 45% off the retail price. The bicycle regularly sells for $115.00. What is the

Pepsi [2]

Answer:

Step-by-step explanation:

100%-45%=55%

$115*55%=$63.25

3 0

2 years ago

find the distance between each pair of points. if necessary, round to the nearest tenth. a(0,3), b(0,12)

statuscvo [17]

The distance between a & b is 3

7 0

3 years ago

Natalie had a job after school. She worked 25 hours a week and got paid $6.25 an hour. How much money would she earn for two wee

erastovalidia [21]

Answer:

312.5

Step-by-step explanation:

25 x 2, for two weeks of work = 50

50 x 6.25 = 312.5

6 0

2 years ago

Read 2 more answers

Determine the number of real solutions for each of the given equations. Equation Number of Solutions y = -3x2 + x + 12 y = 2x2 -

rosijanka [135]

Answer:

Step-by-step explanation:

Our equations are

$y = -3x^2 + x + 12\\y = 2x^2 - 6x + 5\\y = x^2 + 7x - 11\\y = -x^2 - 8x - 16\\$

Let us understand the term Discriminant of a quadratic equation and its properties

Discriminant is denoted by D and its formula is

$D=b^2-4ac\\$

Where

a= the coefficient of the $x^{2}$

b= the coefficient of $x$

c = constant term

Properties of D: If D

i) D=0 , One real root

ii) D>0 , Two real roots

iii) D<0 , no real root

Hence in the given quadratic equations , we will find the values of D Discriminant and evaluate our answer accordingly .

Let us start with

$y = -3x^2 + x + 12\\a=-3 , b =1 , c =12\\D=1^2-4*(-3)*(12)\\D=1+144\\D=145\\D>0 \\$

Hence we have two real roots for this equation.

$y = 2x^2 - 6x + 5\\$

$y = 2x^2 - 6x + 5\\a=2,b=-6,c=5\\D=(-6)^2-4*2*5\\D=36-40\\D=-4\\D$

Hence we do not have any real root for this quadratic

$y = x^2 + 7x - 11\\a=1,b=7,-11\\D=7^2-4*1*(-11)\\D=49+44\\D=93\\$

Hence D>0 and thus we have two real roots for this equation.

$y = -x^2 - 8x - 16\\a=-1,b=-8,c=-16\\D=(-8)^2-4*(-1)*(-16)\\D=64-64\\D=0\\$

Hence we have one real root to this quadratic equation.

7 0

2 years ago

To print tickets, a printer charges a $30 setup fee plus $1.05 per ticket. Write an algebraic expression for the cost of t ticke

arsen [322]

Answer:

Solution given:

we have

setup price =$30

as rate for 1 print tickets =$1.05/tickets

for t

t=$30+$1.05*t

is a required expression.

the

cost of 300 tickets:

300 tickets =$30+$1.05*300=$345

$345is the cost of 300 tickets.

5 0

3 years ago