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3 years ago

5

A hot iron ball is dropped into 200.0 g of cool water. The water temperature increases by 2.0 C and the temperature of the ball

decreases by 18.6 C. What is the mass of the ball? waters specific heat is 4184 (J/kg•C)

1 answer:

Bess [88]3 years ago

7 0

0.2 KG, just search the question and it's on yahoo answers

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In 0.60 seconds, a projectile goes from 0 to 610 m/s. What is the acceleration of the projectile?

IceJOKER [234]

Answer: $a=1016.66 m/s^{2}$

Explanation:

Acceleration $a$ is expressed in the following formula:

$a=\frac{V_{f}-V_{o}}{t}$

Where:

$V_{f}=610 m/s$ is the final velocity of the projectile

$V_{o}=0 m/s$ is the initial velocity of the projectile

$t=0.6 s$ is the time

Solving:

$a=\frac{610 m/s-0 m/s}{0.6 s}$

$a=1016.66 m/s^{2}$ This is the acceleration of the projectile

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4 years ago

Where on Earth might you find these conditions?

Vedmedyk [2.9K]

Which conditions I think you have place an incorrect image?

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3 years ago

As an object fall in a gravitational field, its speed increases. This is an example of potential energy transforming into what?

IrinaK [193]

Answer:

potential energy is transformed into kinetic energy

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3 years ago

b) Two skaters collide and grab on to each other on a frictionless ice. One of them, of mass 80 kg, is moving to the right at 5.

lisabon 2012 [21]

Answer:

The two skaters move with a speed of 1.73 m/s after the collision in the right direction.

Explanation:

Given that,

The mas of skater 1, m₁ = 80 kg

The speed of skater 1, u₁ = 5 m/s (right)

The mass of skater 2, m₂ = 70 kg

The speed of skater 2, u₂ = -2 m/s (left)

Let v is the magnitude of the two skaters just after they collide. They must have a common speed. So, using the conservation of momentum as follows :

$m_1u_1+m_2u_2=(m_1+m_2)v\\\\v=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}$

Put all the values,

$v=\dfrac{80(5)+70(-2)}{(80+70)}\\\\=1.73m /s$

So, the two skaters move with a speed of 1.73 m/s after the collision in the right direction.

8 0

3 years ago

A horse runs a race on a oval track and starts and ends at the same point. He runs one mile track in 7 minutes.

Sergeeva-Olga [200]

Answer:

speed = 8.57mph while v = 0 mph

Explanation:

The horse is running 1 mile in 7 minutes. Then for a total of 1 hour, 60 minutes, the horse should be able to run a distance of

$\frac{1*60}{7} = \frac{60}{7} = 8.57mph$

So the horse speed is 8.57 miles per 60 minutes, or 8.57 mph (mile per hour). But if he ends up at the same point as before int he oval track, one can argue that the displacement is 0, and so is its velocity.

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3 years ago