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melamori03 [73]
3 years ago
7

Tracy has one can of iced tea mix. One scoop of the mix makes two serving of iced tea. The scoop holds 1/12 of a can. How many s

ervings of iced tea can Tracy make?
Mathematics
1 answer:
const2013 [10]3 years ago
5 0
Rhe answer would be 24 because if 12 is the whole can and each scoop then makes 2 times 12=24
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C=r(5-d)/y We need to solve for d.
GrogVix [38]

Answer:

5-Cy/r  = d

Step-by-step explanation:

C=r(5-d)/y

Multiply each side by y

Cy=r(5-d)/y *y

Cy=r(5-d)

Divide each side by r

Cy/r=r(5-d)/r

Cy/r=(5-d)

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Read 2 more answers
Evaluate the indefinite integral. <br> integar x4/1 + x^10 dx
ivann1987 [24]

Answer:

\int\ {\frac{x^4}{1 + x^{10}}} \, dx = \frac{1}{5}( \arctan(x^5)) + c

Step-by-step explanation:

Given

\int\ {\frac{x^4}{1 + x^{10}}} \, dx

Required

Integrate

We have:

\int\ {\frac{x^4}{1 + x^{10}}} \, dx

Let

u = x^5

Differentiate

\frac{du}{dx} = 5x^4

Make dx the subject

dx = \frac{du}{5x^4}

So, we have:

\int\ {\frac{x^4}{1 + x^{10}}} \, dx

\int\ {\frac{x^4}{1 + x^{10}}} \, \frac{du}{5x^4}

\frac{1}{5} \int\ {\frac{1}{1 + x^{10}}} \, du

Express x^(10) as x^(5*2)

\frac{1}{5} \int\ {\frac{1}{1 + x^{5*2}}} \, du

Rewrite as:

\frac{1}{5} \int\ {\frac{1}{1 + x^{5)^2}}} \, du

Recall that: u = x^5

\frac{1}{5} \int\ {\frac{1}{1 + u^2}}} \, du

Integrate

\frac{1}{5} * \arctan(u) + c

Substitute: u = x^5

\frac{1}{5} * \arctan(x^5) + c

Hence:

\int\ {\frac{x^4}{1 + x^{10}}} \, dx = \frac{1}{5}( \arctan(x^5)) + c

7 0
3 years ago
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