You are given two equations, solve for one variable in one of the equations. Say you solved for x in the second equation. Then, plug in that value of x in the x of the first equation. Solve this (first) equation for y (as it should become apparent) and you'll get a number value. Plug in this numerical value of y into the y of the second equation. Solve for x in the second equation. And there you have it: (x, y)
A variable is an unknown like x so
first we start with
x=8
then we subtract (because you must add to reverse subtraction)
x-2=8-2
x-2=6
then we divide ( because you must multiply to reverse division)
(x-2)/3=6/3
(x-2)/3=2
find x
Answer:
5-Cy/r = d
Step-by-step explanation:
C=r(5-d)/y
Multiply each side by y
Cy=r(5-d)/y *y
Cy=r(5-d)
Divide each side by r
Cy/r=r(5-d)/r
Cy/r=(5-d)
Subtract 5 from each side
Cy/r - 5 = 5-d-5
Cy/r - 5 = -d
Multiply by -1
-Cy/r + 5 = d
5-Cy/r = d
Answer:

Step-by-step explanation:
Given

Required
Integrate
We have:

Let

Differentiate

Make dx the subject

So, we have:



Express x^(10) as x^(5*2)

Rewrite as:

Recall that: 

Integrate

Substitute: 

Hence:
