Answer:
B
Explanation:
When it freezes, it will be a solid. The molecules will barely move, not as much as in the other answer choices.
Answer:
Ammonia is an Arrhenius base and a Brønsted-Lowry base.
Explanation:
An Arrhenius base is any substance which, when it is dissolved in an aqueous solution, produces hydroxide (OH^-), ions in solution. An aqueous solution is a solution that has water present in it.
A Bronsted-Lowry base is a substance that accepts a proton, that is, a hydrogen ion (H^+).
Looking at the equation above, ammonia satisfies both characteristics. We can see that when ammonia is dissolved in water, hydroxide ions is produced in the solution. Hence it is an Arrhenius base. Similarly, the hydroxide ion is formed when ammonia accepts a proton. This is a characteristic of a Brownstead-Lowry base. Hence ammonia is both an Arrhenius base and a Brownstead-Lowry base.
Answer:
Here's what I get
Explanation:
There are two methods of naming esters.
(a) Common names
alkyl alcohol + carboxylic acid ⟶ alkyl carboxylate
To form the name of an ester, you drop the alcohol and -ic acid ending from the names of the reactants.
The name of the ester consists of two words: the name of the alcohol followed by the acid name with the ending -ate.
(b) IUPAC (systematic) names
alkanol + alkanoic acid ⟶ alkyl alkanoate
To form the name of an ester, you drop the -anol and -ic acid endings from the names of the reactants.
The name of the ester consists of two words with the corresponding endings -yl and -ate.
You don't mix the common and IUPAC systems in the same name.
1. ethanol + benzoic acid ⟶ ethyl benzoate
2. benzyl alcohol + acetic acid ⟶ benzyl acetate
3. butanol + butanoic acid ⟶ butyl butanoate (IUPAC)
butyl alcohol + butyric acid ⟶ butyl butyrate (common)
4. pentanol + propanoic acid ⟶ pentyl propanoate (IUPAC)
n-pentyl alcohol + propionic acid ⟶ n-pentyl propionate (common)
5. isopropyl alcohol + formic acid ⟶ isopropyl formate
6.023*1023 He atoms=1 mole He
1.23×1024 helium atoms=1.23×1024/6.023*1023 =2.042 mole He
one mole He=4.0 gm
2.042 mole He=2.042*4.0=8.168 gm
answer in grams of Helium is 8.168 gm
