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3 years ago

5

HELP I NEED HELP ASAP

1 answer:

BARSIC [14]3 years ago

3 0

Answer:

I think the answer is letter C

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Evaluate the expression for x = 5, y = 3, and z = 14. <br><br> 5x−6y+20z4yz

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Answer:

5(5)-6(3)+20(14)4(3)(14)

25-18+47040

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Airport A is located on a coordinate plane at (-18, 14). Airport B is located at (8, 14). How far apart are the airports?

Setler [38]

Answer:

26 units

Step-by-step explanation:

Use the distance formula, d = $\sqrt{(x2 - x1)^2 + (y2 - y1)^2$

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d = $\sqrt{(-18 - 8)^2 + (14 - 14)^2$

Simplify:

d = $\sqrt{(-26^2 + (0)^2}$

d = $\sqrt{676}$

d = 26

So, the airports are 26 units apart

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