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svetlana [45]
3 years ago
7

Airport A is located on a coordinate plane at (-18, 14). Airport B is located at (8, 14). How far apart are the airports?

Mathematics
1 answer:
Setler [38]3 years ago
4 0

Answer:

26 units

Step-by-step explanation:

Use the distance formula, d = \sqrt{(x2 - x1)^2 + (y2 - y1)^2

Plug in the points:

d = \sqrt{(-18 - 8)^2 + (14 - 14)^2

Simplify:

d = \sqrt{(-26^2 + (0)^2}

d = \sqrt{676}

d = 26

So, the airports are 26 units apart

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monitta

Answer:

-5

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

45−(5+8y−3(y+3))=−3(3y−5)−(5(y−1)−2y+6)

45+−1(5+8y−3(y+3))=−3(3y−5)+−1(5(y−1)−2y+6)(Distribute the Negative Sign)

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45+−5+−8y+3y+9=−9y+15+−5y+5+2y+−6

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Step 2: Add 12y to both sides.

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7y+49−49=14−49

7y=−35

Step 4: Divide both sides by 7.

7y

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=

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