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3 years ago

Airport A is located on a coordinate plane at (-18, 14). Airport B is located at (8, 14). How far apart are the airports?

Mathematics

1 answer:

Setler [38]3 years ago

4 0

Answer:

26 units

Step-by-step explanation:

Use the distance formula, d = $\sqrt{(x2 - x1)^2 + (y2 - y1)^2$

Plug in the points:

d = $\sqrt{(-18 - 8)^2 + (14 - 14)^2$

Simplify:

d = $\sqrt{(-26^2 + (0)^2}$

d = $\sqrt{676}$

d = 26

So, the airports are 26 units apart

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Step-by-step explanation:

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