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steposvetlana [31]
2 years ago
7

What is the slope of the line that passes through the points

Mathematics
1 answer:
svetoff [14.1K]2 years ago
6 0

Answer:

Step-by-step explanation:

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3 years ago
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madam [21]

Answer-

x=0;y=3

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3 years ago
Write the equation of the circle centered at (3, 5) and tangent to x = -1. I need help pleasse
Annette [7]

Answer:

(x - 3)² + (y - 5)² = 16

Step-by-step explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r the radius

given (h, k ) = (3, 5 ) we require to find r

r is the distance from the centre to a point on the circle

given x = - 1 is a tangent the r is the distance between the x- coordinates

r = | 3 - (- 1) | = | 3 + 1 | = | 4 | = 4

then equation of circle is

(x - 3)² + (y - 5)² = 4² , that is

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2 years ago
Divide. Express the quotient in simplest form.<br><br> (x^2−x−12)/(2x^2)÷(x^2+x−6)/2x^3
e-lub [12.9K]
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6 0
3 years ago
Read 2 more answers
What is 2 5/12 - 1 7/12 =
castortr0y [4]

Answer:

Divide: 7/12  : 3/10  = 7/12  · 10/3= 7 · 10  /12 · 3  = 70/36  = 35/18

To divide one fraction by another, invert (turn upside-down) the second fraction, then multiply.

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4 0
3 years ago
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