1 = 1 x 10 exponent 0
27.5 = 2.75 x 10 exponent 1
Lets write this out:-
2.4 + 0.8 =______ - 0.06 = _____+ 1.21=_____+1.78=_____- 5.14=___
So to solve d blanks we will do d following:-
2.4 + 0.8 = 3.2
Now lets write this out AGAIN.
2.4 + 0.8 = 3.2 - 0.06 = _____+ 1.21=_____+1.78=_____- 5.14=___
Now lets solve again:-
3.2 - 0.06 = 3.14
Now lets write this out AGAIN.
2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21=_____+1.78=_____- 5.14=___
Now lets solve again:-
3.14 + 1.21= 4.25
Now lets write this out AGAIN.
2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78=_____- 5.14=___
Now lets solve again:-
4.25 +1.78= 6.03
Now lets write this out AGAIN.
2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78= 6.03 - 5.14=___
Now lets solve again:-
6.03 - 5.14 = 0.89
Now lets write this out AGAIN.
2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78= 6.03 - 5.14= 0.89
So, 2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78= 6.03 - 5.14= 0.89
Hope I helped ya!! xD
Answer:
0.72
Step-by-step explanation:
Answer:
Two possible solutions
Step-by-step explanation:
we know that
Applying the law of sines
we have
step 1
Find the measure of angle A
substitute the values
The measure of angle A could have two measures
the first measure------->
the second measure ----->
step 2
Find the first measure of angle C
Remember that the sum of the internal angles of a triangle must be equal to
substitute the values
step 3
Find the first length of side c
substitute the values
therefore
the measures for the first solution of the triangle are
,
,
,
step 4
Find the second measure of angle C with the second measure of angle A
Remember that the sum of the internal angles of a triangle must be equal to
substitute the values
step 5
Find the second length of side c
substitute the values
therefore
the measures for the second solution of the triangle are
,
,
,