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stiv31 [10]
3 years ago
13

Given the lengths of the sides which of the following would NOT be a right triangle?

Mathematics
1 answer:
zmey [24]3 years ago
5 0
• 9.12.16
&
• 33,45,55
You might be interested in
The measure of two vertical angles are 6x - 22 and 4x + 2. Find x.
maks197457 [2]
Vertical angles are congruent...they are equal....so set them equal to each other and solve for x

6x - 22 = 4x + 2
6x - 4x = 2 + 22
2x = 24
x = 24/2
x = 12 <==



6 0
3 years ago
Explain how modeling partial products can be used to find the products of greater numbers.
beks73 [17]
<span>It is easier to multiply. For example: 63 multiply by 7
</span><span>63 x 7 = (60+3) x 7 =  60 x 7 + 3 x 7 =  420 + 21  =  441
</span>
Another example : <span>25 x 73
</span>25 x 73 = (20+5) x (70+3) = 20 x 70 + 20x3 + 5x70 + 5x3

                                         = 1400 + 60 + 350 + 15           =  1875


8 0
3 years ago
Melinda rod her bike 54/100 mile to the library. then she rode 4/10 mile to the store. how far did Melinda ride her bike in all?
Lady_Fox [76]
94/100 miles is the answer. I dont know what form you wanted the answer in but yeah.
3 0
3 years ago
Shawna won 40 super bouncy balls playing
patriot [66]

Answer:

13 not including Shawna

Step-by-step explanation:

First, you have to take into account that the remainder is 1, so you must subtract 1 from 40, giving you 39. 39/3 is 13, so 13 is your final answer.

5 0
2 years ago
Read 2 more answers
Laura drove 638 miles in 11 hours at the same rate how long would it take her to drive 406 miles
shusha [124]

Answer:

Step-by-step explanation:

This is a d = rt problem; but since it is linear, then proportions will work too. Set up the proportion with miles on top and hours on the bottom:

\frac{miles}{hrs}:

Then put the numbers in where they go, keeping in mind that miles goes with miles and hours goes with hours in the ratios, and that our unknown is time (hours):

\frac{miles}{hrs}:\frac{638}{11}=\frac{406}{x} and cross multiply to solve:

638x = 4466 so

x = 7 hrs

6 0
2 years ago
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