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Bess [88]
3 years ago
14

PLEASE ANSWER

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
8 0

Answer:

6/5 hours

Step-by-step explanation:

<u>GIVEN :-</u>

Lets say ,

  • Pump A takes 2 hours to fill the tank alone
  • Pump B takes 3 hours to fill the tank alone

<u>TO FIND :-</u>

  • Time taken by both pumps to fill the tank when used together

<u>PROCEDURE :-</u>

In 2 hours , Pump A fills the whole tank.

⇒ In 1 hour , Pump A will fill 1/2 part of tank. (By using Unitary method)

In 3 hours , Pump B fills the whole tank.

⇒ In 1 hour , Pump B will fill 1/3 part of tank. (By using Unitary method)

In 1 hour , when both pumps will be used together , they will fill =

(Part of tank filled by A in 1hr) + (Part of tank filled by B in 1hr)

⇒  \frac{1}{2} + \frac{1}{3}

=> \frac{5}{6} part of tank

5/6 part of tank will be filled by both the pumps in = 1 hour.

Using unitary method, multiplying both the sides with 6/5 -

⇒ 5/6 × 6/5 part of tank will be filled by both the pumps in = 1 × 6/5 hours

⇒ Total tank (or 1 whole tank) will be filled by both the pumps in = 6/5 hours

∴ Both the pumps will take 6/5 hour to fill the tank , when used together.

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