Answer:
Explanation:
When the person stands 5.80 ft from the mirror of the wall.
a) The first image is found by multiplying the distance of the left mirror to the person.
i.e.
2 × 5.80 = 11.6 ft
b) The second image is deduced by the addition of the distance of the first image with the distance created by the right mirror.
i.e.
(2 × 13.7 ) + 11.6
= 39 ft
c) The third image is acquired by the addition of the image presented by the left mirror and the image presented by the right mirror.
(2 × 5.80) + 39
= 50.6 ft
Answer:
a) -2.1731 m⁻s
Explanation:
L= length of thread, H= height of ball from ceiling,
N/B h= l cosФ, Ф=31°, l=2.7m, g=9.8m⁻s, m= 6kg
Required to find speed v, of the ball in m⁻s
ω=√g/h, =√g/lcosФ
⇒ ω=√9.8/2.7×cos31°
= 1.992rad⁻s
Now, speed in m/s, v= r.ω
where tanФ= r/h ⇒
r= h×cos 31°
r= 2.7 × cos(31) × tan(31) =-1.0909m
v= 1.992× -1.0909 = -2.1731 m/s
Hi!
The answer would be 22.5m
<h3>Explanation</h3>
To calculate the distance the ball travels, you would need to apply the following formula from the equations of motion for an accelerating object:
2as = v^2 - u^2
Where a is acceleration due to gravity, 9.8m/s^2
s is the distance traveled by the object (height of ball in this case)
v is the final velocity, which we know will be zero at the point where the ball reaches maximum height.
u is the initial velocity, which is known to us as 21m/s
Rearranging the equation to solve for the height:
s = (v^2 - u^2 ) / 2a
s = ( 0^2 - 21^2 ) / 2(-9.8)
s = - 441/ - 19.6
s = 22.5m
<em>Note: since gravity is acting against the object's motion, it will be negative </em>
<em>Hope this helps!</em>
