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BigorU [14]
3 years ago
6

Electrical Safety: What should you do to a hot plate before turning it on? More than one answer may be correct. Check that the l

ead does not trail in liquid. Check the cable for exposed wires. Position in a stable place away from places where it could be knocked over. Wipe any oil residues off the hot plate.
Physics
1 answer:
solniwko [45]3 years ago
8 0

Answer and Explanation:

Before turning a hot plate on, one should consider these points:

  • Check for the leads and ensure they does not trail in liquid.
  • The cable should be checked for any exposed wire before turning on in order to prevent any shock.
  • Any oil residue should be wiped off of the hot plate to ensure its longevity.
  • It should be placed in a stable place in order to ensure safety against any hazard.
  • Thus all the above mentioned points are correct to ensure safety.
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The volume decreases, by a factor of

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A container with volume 1.64 L is initially evacuated. Then it is filled with 0.226 g of N2N
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Answer:

0.015 atm

Explanation:

The pressure of the gas can be calculated using Ideal Gas Law:

p = \frac{nRT}{V}

<u>Where:</u>

n: is the number of moles of the gas

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V: is the volume of the container = 1.64 L

T: is the temperature

We need to find the number of moles and the temperature. The number of moles is:

n = \frac{m}{M}

<u>Where:</u>

M: is the molar mass of the N₂ = 14.007 g/mol*2 = 28.014 g/mol

m: is the mass of the gas = 0.226 g

n = \frac{0.226 g}{28.014 g/mol} = 8.07 \cdot 10^{-3} moles

Now, the temperature can be found using the following equation:

v_{rms} = \sqrt{\frac{3RT}{M}}    

<u>Where:</u>

R: is the gas constant = 0.082 L*atm/K*mol = 8.314 J/K*mol

v_{rms}: is the root-mean-square speed of the gas = 182 m/s

By solving the above equation for T, we have:

T = \frac{v_{rms}^{2}*M}{3R} = \frac{(182 m/s)^{2}*28.014 \cdot 10^{-3} Kg/mol}{3*8.314 J K^{-1}mol^{-1}} = 37.20 K        

Finally, we can find the pressure of the gas:

p = \frac{nRT}{V} = \frac{8.07 \cdot 10^{-3} mol*0.082 L*atm* K^{-1}*mol^{-1}*37.20 K}{1.64 L} = 0.015 atm

Therefore, the pressure of the gas is 0.015 atm.

I hope it helps you!

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