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hodyreva [135]
3 years ago
7

5y(4y^2−2y)+3y(−2y^2+4y)Please help

Mathematics
1 answer:
Alona [7]3 years ago
5 0

Answer:

factor the expression =2y^2 (7y+1) or simplify it=14y^3 + 2y^2

Step-by-step explanation:

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Calculate the length of the circumference of a circle with a diameter of 7 cm
AysviL [449]
<span>C = 21.98 cm......... </span>
3 0
3 years ago
Inverse equation t=120r/r+120 R=???
Komok [63]

9514 1404 393

Answer:

  r = 120t/(120-t)

Step-by-step explanation:

Multiply by the denominator, isolate r terms, then divide by the coefficient of r.

  t=\dfrac{120r}{r+120}\qquad\text{given}\\\\t(r+120)=120r\qquad\text{multiply by $(r+120)$}\\\\120t=120r-tr\qquad\text{subtract $tr$}\\\\\dfrac{120t}{120-t}=r\qquad\text{divide by the coefficient of $r$}\\\\\boxed{r=\dfrac{120t}{120-t}}

7 0
3 years ago
Help please I can’t figure it put
leonid [27]

5y + 3 >  -7 y + 13

Subtract 3 from both sides

5y > -7y + 13 - 3

Add 7y to both sides

5y + 7y > 13 - 3

12y > 10

Divide by 12, which is positive so the sign doesn't flip

y > 10/12 = 5/6

Answer: y > 5/6


8 0
3 years ago
Does anyone know the answer to this? i’ll mark brainliest
Ilia_Sergeevich [38]

Answer:

It is greater

Step-by-step explanation:

6 0
3 years ago
on marks first day, he ran 5 laps without stopping after several weeks of training he ran 9 weeks without stopping. what is the
tino4ka555 [31]

The percentage increase from 5 laps of race on the first day to 9 laps after several weeks is 80%

<h3>How to determine the percentage increase?</h3>

The distance ran are given as:

Initial = 5 laps

Final= 9 laps

The percentage increase is calculated using:

Percentage = (Final - Initial)/Initial

So, we have:

Percentage = (9 - 5)/5

Evaluate

Percentage = 0.8

Express as percentage

Percentage = 80%

Hence, the percentage increase is 80%

Read more about percentage increase at:

brainly.com/question/11360390

8 0
2 years ago
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