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2 years ago

Wendy paints a rectangular wall that is 10.5 feet tall and 9.2 feet wide. What is the area of the wall that she paints?

Mathematics

2 answers:

algol [13]2 years ago

6 0

Answer:

96.6

Step-by-step explanation:

We know that the Area of the rectangle is,

A =Length x width

So the Area of the wall painted by Wendy will be,

A = 10.5 x 9.2 = 96.6

So; the area painted by Wendy will be <em><u>96.6 square feet</u></em>.

-Mark me brainliest and a 5 star :D

natka813 [3]2 years ago

3 0

96 and six we know that the area is a equals one laying eggs with

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3 years ago

PLEASE HELP ASAP

maria [59]

Answer:

First option: $3x^2-5x=-8$

Second option: $2x^2=6x-5$

Fourth option: $-x^2-10x=34$

Step-by-step explanation:

Rewrite each equation in the form $ax^2+bx+c=0$ and then use the Discriminant formula for each equation. This is:

$D=b^2-4ac$

1) For $3x^2-5x=-8$ :

$3x^2-5x+8=0$

Then:

$D=(-5)^2-4(3)(8)=-71$

Since $D$ this equation has no real solutions, but has two complex solutions.

2) For $2x^2=6x-5$ :

$2x^2-6x+5=0$

Then:

$D=(-6)^2-4(2)(5)=-4$

Since $D$ this equation has no real solutions, but has two complex solutions.

3) For $12x=9x^2+4$ :

$9x^2-12x+4=0$

Then:

$D=(-12)^2-4(9)(4)=0$

Since $D=0$ this equation has one real solution.

4) For $-x^2-10x=34$ :

$-x^2-10x-34=0$

Then:

$D=(-10)^2-4(-1)(-34)=-36$

Since $D$ , this equation has no real solutions, but has two complex solutions.

3 0

3 years ago