Evaluate 3 7 r + 5 8 s 7 3 r+ 8 5 sstart fraction, 3, divided by, 7, end fraction, r, plus, start fraction, 5, divided by, 8
bazaltina [42]
Answer:
Therefore the value of given expression when r = 14 and s = 8 is
![\dfrac{3}{7}\times r + \dfrac{5}{8}\times s=11](https://tex.z-dn.net/?f=%5Cdfrac%7B3%7D%7B7%7D%5Ctimes%20r%20%2B%20%5Cdfrac%7B5%7D%7B8%7D%5Ctimes%20s%3D11)
Step-by-step explanation:
Given:
![\dfrac{3}{7}\times r + \dfrac{5}{8}\times s](https://tex.z-dn.net/?f=%5Cdfrac%7B3%7D%7B7%7D%5Ctimes%20r%20%2B%20%5Cdfrac%7B5%7D%7B8%7D%5Ctimes%20s)
To Find:
Value of above equation when r = 14 and s = 8
Solution:
.............Given
Put,
![r=14\\s=8](https://tex.z-dn.net/?f=r%3D14%5C%5Cs%3D8)
![\dfrac{3}{7}\times r + \dfrac{5}{8}\times s=\dfrac{3}{7}\times 14 + \dfrac{5}{8}\times 8](https://tex.z-dn.net/?f=%5Cdfrac%7B3%7D%7B7%7D%5Ctimes%20r%20%2B%20%5Cdfrac%7B5%7D%7B8%7D%5Ctimes%20s%3D%5Cdfrac%7B3%7D%7B7%7D%5Ctimes%2014%20%2B%20%5Cdfrac%7B5%7D%7B8%7D%5Ctimes%208)
Now 7 × 2 = 14 and 8 will cancel each other we get
![\dfrac{3}{7}\times r + \dfrac{5}{8}\times s=3\times 2 + 5=6+5=11](https://tex.z-dn.net/?f=%5Cdfrac%7B3%7D%7B7%7D%5Ctimes%20r%20%2B%20%5Cdfrac%7B5%7D%7B8%7D%5Ctimes%20s%3D3%5Ctimes%202%20%2B%205%3D6%2B5%3D11)
Therefore the value of given expression is
![\dfrac{3}{7}\times r + \dfrac{5}{8}\times s=11](https://tex.z-dn.net/?f=%5Cdfrac%7B3%7D%7B7%7D%5Ctimes%20r%20%2B%20%5Cdfrac%7B5%7D%7B8%7D%5Ctimes%20s%3D11)
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Let's solve your equation step-by-step.
3−6(x−7)=42−6x
Step 1: Simplify both sides of the equation.
3−6(x−7)=42−6x
3+(−6)(x)+(−6)(−7)=42+−6x(Distribute)
3+−6x+42=42+−6x
(−6x)+(3+42)=−6x+42(Combine Like Terms)
−6x+45=−6x+42
−6x+45=−6x+42
Step 2: Add 6x to both sides.
−6x+45+6x=−6x+42+6x
45=42
Step 3: Subtract 45 from both sides.
45−45=42−45
0=−3
Therefore, this is No Solutions.
The theoretical probability of tossing a heads with one coin is 1/2 since there are 2 sides. You have to multiply 1/2*1/2, because there are now two coins. 1/2*1/2=1/4 so the probability of rolling 2 heads on 2 coins is 1/4. The probability of rolling a 2 or 5 on a dice is 2/6 or 1/3. This is because there is a total of 6 sides on a dice and 2 or 5 are 2 possibilities so the probability would be 2/6. You can simplify this to 1/3. You now have to multiply 1/4*1/3 since it says 2 heads with 2 coins. 1/4*1/3=1/12. 1/12 is your final answer.